CHAPTER I

PROPERTIES OF THE TRIANGLE

A LIST of the fundamental formulae connecting the elements of a triangle, proofs of which have been given in Durell and Wright’s Elementary Trigonometry, will be found in Section D of the formulae at the beginning of that book ; references to these proofs will be indicated by the prefix E.T.

For geometrical proofs of theorems on the triangle, the reader is referred to some geometrical text-book. When these theorems are quoted or illustrated in this chapter, references, indicated by the prefix M.G., are given to Durell’s Modern Geometry.

Revision.  Examples for the revision of ordinary methods of solving a triangle are given in Exercise I. a, below.

It is sometimes convenient to modify the process of solution. If, for example, the numerical values of b, c, A are given and if the value of a only is required, we may proceed as follows :

 

images

 

image

where

 

image

θ is first found from (2) and then a is obtained from (1), both equations being adapted to logarithmic work.

An angle θ, used in this way, is called a subsidiary angle. For other examples of the use of subsidiary angles, see Ex. I. a, Nos. 21 to 25.

EXERCISE I. a.

[Solution of Triangles]

1. What are the comparative merits of the formulae for cos A, cosimages, sinimages, tanimages, when finding the angles of a triangle from given numerical values of a, b, c ?

2. Given a = 100, b = 80, c = 50, find A.

3. Given a = 37, b = 61, c = 37, find B.

4. Given a = 11·42, b = 13·75, c = 18·43, find A, B, C.

5. Given A = 17° 55′, B = 32° 50′, c = 251, find a from the formula a = c sin A cosec C.

6. Given B = 86°, C = 17° 42′, b = 23, solve the triangle.

7. Given b = 16·9, c = 24·3, A = 154° 18′, find images(B – C) from the formula images, and complete the solution of the triangle.

8. Given b = 27, c = 36, A = 62° 35′, find a.

Solve the triangles in Nos. 9-13 :

9. A = 39° 42′, B = 81° 12′, c = 47·6.

10. b = 6·32, c = 8·47, B = 43°.

11. a = 110, b = 183, c = 152.

12. a = 6·81, c = 9·06, B = 119° 45′.

13. b = 16·9, c = 12·3, C = 51°.

[The Ambiguous Case]

14. Given A = 20° 36′, c = 14·5, find the range of values of a such that the number of possible triangles is 0, 1, 2. Complete the solution if a equals (i) 8·3, (ii) 16·2, (iii) 3·2, (iv) 5·1.

15. Given b, c, and. B, write down the quadratic for a, and the sum and product of its roots, a1 and a2. Verify the results geometrically.

 

images

If A1, C1 and A2, C2 are the remaining angles of the two triangles which satisfy the data, find C1 + C2 and A1 + A2.

16. With the data of No. 15, prove that

 

images

17. With the data of No. 15, prove that

 

images

18. (i) With the data of No. 15, if a1 = 3a2, prove that

 

images

(ii) With the data of No. 15, if C2 = 2C1, prove that

 

images

19. If the two triangles derived from given values of c, b, B have areas in the ratio 3 : 2, prove that 25 (c2b2) = 24c2 cos2B.

20. With the data of No. 15, if A1 =2A2, prove that 4c3 sin2 B = b2(b +3c).

 

images

[Subsidiary Angles]

21. Given b = 16·9, c = 24·3, A = 154° 18′, find a from formulae (1) and (2), p. 1.

22. Show that the formula c = b cos A± images(a2b2 sin2 A) may be written in the form c = a sin (θ ± A) cosec A, where images.

23. Show how to apply the method of the subsidiary angle to a2 = (bc)2 + 2bc(l – cos A).

24. In any triangle, prove that tan images(B – C) = tan (45° – θ)cot imagesA, where images.

Hence find images(B – C) if b = 321, c = 436, A = 119° 15′.

25. Express a cos θb sin θ in a form suitable for logarithmic work.

[Miscellaneous Relations]

26. If a = 4, b = 5, c = 6, prove that C = 2A.

27. Express in a symmetrical form images.

28. Prove that b2(cot A + cot B) = c2(cot A + cot C).

29. Simplify cosec (A – B) . (a cos B – b cos A).

30. Prove that a2 sin (B – C) = (b2c2) sin A.

31. Prove that images.

32. If b cos B = c cos C, prove that either b = c or A = 90°.

33. Prove that sin2 A + sin B sin C cos A = images.

34. Prove that images.

35. Prove that

 

images

36. Express cos images(A – B). cosec images in terms of a, b, c,

37. If b + c = 2a, prove that 4Δ = 3a2 tan images.

38. If a2 = b(b + c), prove that A = 2B.

39. Prove that c2 = a2 cos 2B + b2 cos2A + 2ab cos(A – B).

40. Prove that images.

41. Prove that

 

images

42. If cos A cos B + sin A sin B sin C = 1, prove that A = 45° = B.

The Circumcentre.  The centre O of the circle through A, B, C is found by bisecting the sides of the triangle at right angles, and the radius is given by the formulae

 

images

 

image

 

image

The reader should prove that these formulae hold also when images BAC is obtuse.

The in-centre and e-centres. The centres I, I1, I2, I3 of the circles which touch the sides are found by bisecting the angles of the triangle, internally and externally.

 

FIG. 2.

images

 

images

FIG. 3.

The radii of these circles are given by

 

image

 

image

Also in Fig. 3, we have

 

image

 

image

For proofs of these formulae and further details, see E.T., pp. 184·186, 277, 278 and M.G., pp. 11, 24, 25.

The Orthocentre and Pedal Triangle. The perpendiculars AD, BE, CF from the vertices of a triangle to the opposite sides meet at a point H, called the orthocentre ; the triangle DEF is called the pedal triangle (M.G., p. 20).

 

images

FIG. 4.

 

images

FIG. 5.

If Δ ABC is acute-angled, (Fig. 4), H lies inside the triangle.

Since BFEC is a cyclic quadrilateral, AFE and ACB are similar triangles ;

 

image

Since HECD is a cyclic quadrilateral, images HDE = images HCE = 90° – A ; similarly images HDF = 90° – A ;

 

image

Further, HD bisects images EDF and similarly HE bisects images DEF ; ∴ H is the in-centre of Δ DEF. Also since BC is perpendicular to AD, it is the external bisector of images EDF ; hence A, B, C are the e-centres of the pedal triangle.

We have also

 

image

and

 

image

The reader should work out the corresponding results for Fig. 5, where the triangle is obtuse-angled.

If images BAC is obtuse, images EDF = 2A – 180° and other results are modified by writing – cos A for cos A. [See Ex. I. b, No. 27 and note the difference of form in No. 36. See also Example 3.]

The Nine-Point Circle.  The circle which passes through the midpoints X, Y, Z of the sides BC, CA, AB passes also through D, E, F and through the mid-points of HA, HB, HC ; it is therefore called the nine-point circle and its centre N is the mid-point of OH (M.G., p. 27).

 

images

FIG. 6.

Since Δ XYZ is similar to Δ ABC and of half its linear dimensions, the radius of the nine-point circle is imagesR.

Since each of the points H, A, B, C is the orthocentre of the triangle formed by the other three, the circumcircle of Δ DEF is the common nine-point circle of the four triangles ABC, BCH, CHA, HAB.

Also, since Δ ABC is the pedal Δ of Δ I1I2I3 and of Δ II2I3, etc., the circumradius of each of these triangles is 2R.

The Polar Circle.  In Fig. 6 and Fig. 7 we have, by cyclic quadrilaterals,

 

images

In Fig. 7, where images BAC is obtuse, A and D are on the same side of H, and so also are B, E and C, F. In this case, if HA . HD = p2, it follows that the polars of A, B, C w.r.t. the circle, centre H, radius ρ, are BC, CA, AB.

The triangle ABC is therefore self polar w.r.t. this circle ; and the circle is called the polar circle of Δ ABC.

 

images

FIG. 7.

We have

 

image

An acute-angled triangle in real geometry has no polar circle.

Notation.  The lettering already adopted for special points connected with the triangle will be employed throughout the Chapter. This will shorten the statement of many of the examples.

We add some illustrative examples.

Example 1. Prove s2 = Δ(cot imagesA + cot imagesB + cot imagesC).

Since

 

images

Example 2. Express images in a symmetrical form.

Since

 

images

Example 3. If J is the in-centre of BHC, express the radius of the circle BJC in terms of R and A.

By equation (3) the radius is imagesBC cosec BJC, but

images BJC = 90° + images images BHC = 180° – imagesA, if B and C are acute angles;

 

images

If either B or C is obtuse, imagesBJC = 90° + imagesA, and then the radius = 2R sin imagesA.

EXERCISE I. b.

1. If a = 15·1, A =24° 36′, find R.

2. If a = 3, b = 5, c = 7, find R and r.

3. If a = 13, b = 14, c = 15, find r1, r2, r3.

4. If a = 23×5, A = 62°, and b = c, find R and r.

5. Prove that

 

images

6. Verify Equation (6), p. 4, by using the formulae sin images, cos images, etc., in terms of the sides.

7. Express a (cos A + cos B cos C) in a symmetrical form.

Prove the following relations :

8. images

9. images

10. r2r3 tan images = Δ.

11. r2r3 + r3r1 + r1r2 = s2.

12. r2 + r3 = 4R cos2 images.

13. rr1 + r2 + r3 = 2a cot A.

14. AI . AI1 = bc.

15. IA. IB = 4Rr sin images.

16. IA. IB. IC = images.

17. II1. II2. II3 = 16R2r.

18. Δ ABI : Δ ACI = c : b.

19. AD2 (cot B + cot C) = 2Δ.

20. AD = 2r cosec images cos images cos images.

21. Δ OI2I3 : Δ OI3I1 = (b + c) : (a + c).

22. AH = α cot A = 2OX.

23. AH + BH +CH = 2 (R + r).

24. If a = 14, b = 13, c = 15, prove that AD = 12.

25. Given B = 37°, C =46°, BE = 9×3, find 6.

26. If BP . PC = Δ, (see Fig. 3), prove that A =90°.

27. In Fig. 5, where imagesBAC is obtuse, prove that

(i) EF = –a cos A, FD = b cos B, DE = c cos C ;

(ii) imagesFDE = 2A – 180°, images DEF = 2B, images EFD = 2C;

(iii) AH = – 2R cos A, BH = 2R cos B, CH = 2R cos C;

(iv) HD = 2R cosB cos C, HE = – 2R cos C cos A,
HF = – 2R cos A cos B.

28. If a = 13, b = 9, c = 5, find ρ (see p. 6).

29. Find an expression for the radius of the polar circle of Δ II2 I3 in terms of R, r1.

30. Prove that the circumradius of Δ HBC equals R.

31. Prove that the circumradius of Δ OBC is > imagesR.

32. Prove that the in-radius of Δ AEF is r cos A.

33. Prove that the area of Δ DEF is ± 2A cos A cos B cos C.

34. Given b, c, B, prove that the product of the in-radii of the two possible triangles is c (cb) sin2 imagesB.

35. Prove that the in-radius of Δ I1I2I3, is images.

36. If Δ ABC is acute-angled, prove that the perimeter of Δ DEF is 4R sin A sin B sin C. If images BAC is obtuse, prove that the perimeter is 4R sin Δ cos B cos C.

37. Find in terms of A, B, C, R the in-radius of Δ DEF (i) if Δ ABC is acute-angled, (ii) if images BAC is obtuse.

38. Prove that a sin B sin C + b sin C sin A + c sin A sin B = images.

39. Express images + r Cos A – R cos2 A in a symmetrical form.

40. Prove that

(i) a2 cos2 A = b2 cos2 B + c2 cos2 C + 2bc cos B cos C cos 2A;

(ii) a2 cos2 A cos2 2A = b2 cos2B cos2 2B + c2 cos2 C cos2 2C + 2bc cos B cos C cos 2B cos 2C cos 4A;

(iii) a2 cosec2 images = b2 cosec2 images + c2 cosec2 images – 2bc cosec images cosec images sin images.

Any Line through a Vertex. Suppose any line through A cuts BC at K. Denote images by images, so that K is the centroid of masses y, z at B, C respectively.

Let images BAK = β, images KAC = γ, imagesAKC = θ.

Draw BB′, CC′ perpendicular to AK.

Then

 

images

 

images

FIG. 8.

This may be written

 

images

This relation, which determines θ for a given triangle and given position of K, is often useful in three-force problems in statics (cf. Ex. I. c, No. 11) ; an alternative method of proof is indicated in Ex. I. c, No. 8. Sometimes (cf. Ex. I. c, No. 12) it is convenient to have an expression for θ in terms of β, γ.

From (14),

 

images

The Centroid. The centroid of k1 at (x1, y2), k2 at (x2, y2), k3 at (x3, y3), etc., is the centre of mass of particles of masses proportional to k1, k2, k3, etc., at these points. The centroid is also called the centre of mean position. The point may also be defined geometrically, and its coordinates are images; thus the idea of mass is not really involved. The values of the k’s need not all be positive, but ∑k must not be zero. (M.G., pp. 58-64.)

If T is any point in AK, we have with the notation of Fig. 9,

 

images

∴ K is the centroid of Δ CTA at B and Δ ATB at C;

 

images

FIG. 9.

∴ the centroid of Δ BTC at A, Δ CTA at B, Δ ATB at C lies on AK, that is on AT ; similarly it must lie on BT, and it is therefore at T.

Hence, if any point T is the centroid of masses λ, μ, v at A, B, C, then λ : μ: v = Δ TBC : Δ TCA : Δ TAB.

If, with the same notation as before, K is the centroid of y at B and z at C, the length of AK is given by a theorem of Apollonius (M.G., p. 61):

 

images

where

 

images

And more generally (M.G., p. 62) if G is the centroid of k1 at P1, k2 at P2, etc., and if O is any point,

 

images

Equation (19) is useful in dealing with expressions connected with Δ ABC of the form λ .TA2 + μ .TB2 + v .TC2. (Cf. Ex. I. c, Nos. 39, 40 and Ex. I. d, Nos. 22-28.)

Medians. If y = z, AK is a median ; we then have from (15) and (18)

 

images

 

images

The three medians of a triangle are concurrent at a point G, which is the centroid of equal masses at A, B, C or of equal masses at X, Y, Z

Further GX = imagesAX and in addition G is the point on OH such that OG = imagesOH.   (M.G., p. 28.)

 

images

FIG. 10.

 

images

FIG. 11.

Angle-Bisectors. If AK1 is the internal bisector of images BAC, β = γ = imagesA and θ = B + imagesA = 9O° – images(C–B).

Also z: y = c : b; ∴ from (18), we have

 

images

If AK2 is the external bisector of images BAC,

 

images

Also z : y = c : – b; ∴ from (18) as before, we have

 

images

Direct methods of proof are indicated in Ex. I. c, Nos. 15, 16.

Example 4. Show that ∑ cot AXC = 0

 

images

Equation (20) gives

 

images

and equation (16), with y = z, gives

 

images

from which the required results follow.

Example 5. Find what masses at the vertices have their centroid at the circumcentre, and deduce that, if S is on the circle ABC,

 

images

The area BOC = imagesR2 sin 2A;

∴ the ratios of the areas BOC, COA, AOB are

 

images

∴ the masses are proportional to sin2A, sin2B, sin2C (see p. 10). Hence, by equation (19),

 

images

EXERCISE I. c.

1. If AO meets BC at K, prove that images.

2. If K is a point on the base BC of an equilateral triangle ABC and if images BAK = 15°, calculate images.

3. If B = C = 30° and if the perpendicular at A to AC cuts BC at K, prove that BK = imagesKC.

4. If a = 13, b = 14, c = 15, find cot B, cot C and cot AXC.

5. If a = 61, b = 11, c = 60 and if K divides BC internally as 3 : 2, find cot AKC.

6. If a = 85, b = 13, c = 84 and if K divides BC externally as 3 : 2, find cot AKC.

7. Prove that tan AXC = images.

8. If B, K, D, C are any four collinear points, prove that

 

images

From this relation, deduce equation (15) on p. 9.

9. Prove that abc cot AXB = R(b2c2).

10. If the trisectors of images BAC meet BC in K, K′, prove that

 

images

11. A uniform rod AB, 1 ft. long, is suspended from O by strings OA, OB of lengths 10 in., 7 in. ; find the angle between AB and the vertical.

12. A uniform rod AB rests with its ends on two smooth planes, as shown ; XOY is horizontal, find the angle between AB and the vertical.

 

images

FIG. 12.

13. If a = 5, b = 4, c = 6 and if K divides BC internally as 3:2, find AK.

14. If images XAC = 90°, prove that tan A + 2 tan C =0.

15. If the internal bisector of images BAC meets BC at K, prove that images(b + c). AK sin images = Δ, and deduce that images, and that

 

images

16. If the external bisector of images BAC meets BC produced at K′, prove that images(cb). AK′ cos images = Δ, and deduce that

 

images

17. If the internal bisector of images BAC meets BC at K, prove that

(i) AI : IK =(b + c) : a;

(ii) a . PD =(cb) (sa);

(iii) tan APC = images.

18. If the internal bisector of images BAC meets BC at K and the circumcircle at L, prove that AL = images(b + c)sec images. Find AK . AL and show that

 

images

19. Find the areas of Δ BOC, Δ BHC and deduce the area of Δ BNC. If AN meets BC at K, find images.

20. Show that I is the centroid of a at A, b at B, c at C.

21. What is the centroid of – a at A, b at B, c at C ?

22. If H is the centroid of x at A, y at B, z at C, find x : y : z

23. Find the centroid of

(i) 1 at A, 1 at B, 1 at C, 1 at H ;

(ii) 3 at G, –2 at O.

24. Prove that AX2 + BY2 + CZ2 = images(a2 + b2 + c2).

25. If BY is perpendicular to CZ, prove that b2 + c2 = 5a2.

26. Prove that tan BGC = images.

27. If BY cuts AD at T, prove that AT = images.

28. If B = 55°, C = 23° 30′, AX =40, prove that BYimages60.

29. If A = 90°, and if BC is trisected at Tl, T2, prove that

 

images

30. If A = B = 45° and if K is on AB, prove that AK2 + BK2 = 2CK2.

31. If AX = m, AD = h, prove that images.

32. If images BAX = β, images CAX = γ, prove that tan images tan images.

33. If the internal bisectors make angles θ, ϕ, Ψ with the opposite sides, prove that a sin 2θ + b sin 2ϕ + c sin 2Ψ = 0.

34. Prove that 3 cot BGC = cot A – images.

35. If C = 2B and if CB is divided externally at Q in the ratio 4:1, prove that AQ – AC = imagesQC.

36. If A, B, C, D are collinear and O is any point, prove that

 

images

37. If AU, BV, CW are concurrent lines cutting BC, CA, AB at U, V, W, prove that

 

images

38. If three segments AB, BC, CD of a straight line are of lengths α, β, γ and subtend equal angles θ at a point P, prove that

 

images

39. (i) Use equation (19) and No. 20 to show that

 

images

(ii) For what position of T is TA2 + TB2 + TC2 least ?

40. What is the locus of T, if

 

images

is constant ?

Distances between Special Points. With the usual notation,

 

images

 

images

FIG. 13.

To find OI2 (M.G., p. 35).

Let C be one of the acute angles of the triangle ABC.

 

images

 

images

In the same way it can be proved that

 

images

To find OH2.

For an acute-angled triangle ABC, images OAB = 90° – C, images HAB = 90° –B,

 

images

If A > 9°, images HAB = 90° + B; ∴ cos OAH = –cos (C – B); also

 

images

∴ the final result is the same as before.

To find I1H2.

For an acute-angled triangle ABC, images I1AH = images ~ (90° – C) = images;

 

images

In the same way it can be proved that

 

images

The reader should verify that these results are also true for an obtuse-angled triangle.

A geometrical method of proof of (24) is indicated in Ex. I. d, No. 21.

The reciprocity of the relations (24) and (26) is explained by the following argument: since Δ ABC circumscribes its own in-circle and is self-polar w.r.t. its own polar circle, there exists a triangle αβγ which is inscribed in this polar circle, and is self-polar w.r.t. this in-circle (Durell’s Projective Geometry, p. 209).  ∴ H is the circumcentre, ρ is the circumradius, I is the orthocentre, r is the polar-radius of Δ αβγ.

∴applying (24) to Δ αβγ, we have HI2 = ρ2 +2r2.

To find IN.

 

images

FIG. 14.

The nine-point centre N is the mid-point of OH ;

 

images

But OI2 = R(R – 2r); ∴ R ≥ 2r;

 

images

In the same way it can be proved that.

 

images

Since the radius of the nine-point circle is imagesR, equations (27) and (28) prove that the nine-point circle touches the in-circle and the escribed circles [Feuerbach’s Theorem, M.G., p. 117].

Example 6. If IH is parallel to BC, find a relation between the cosines of the angles of the triangle.

I and H will be equidistant from BC, thus r = 2R cos B cos C, thus

 

images

Example 7. Express IG in terms of the radii of the various circles connected with the triangle.

By equation (19) we have, since G is the centroid of 2 at O and 1 at H, (see Fig. 14)

 

images

EXERCISE I. d.

1. If OI is parallel to BC, prove that cos B + cos C = 1.

2. If IG is parallel to BC, prove that r1 = 3r.

3. Prove OI2 = R2 [3 – 2∑(cos A)].

4. Prove II12 = 4R (r1r) and I2I32 = 4R (r2 + r3).

5. Prove II22 + I1I32 = II32 + I1I22.

6. Prove OH2 = 9R2a2b2c2.

7. If A = 60°, prove OH2 = (3R + 2r) (R – 2r).

8. Prove tan IAX = tan2images tanimages.

9. If in a scalene triangle IG is perpendicular to BC, prove that

 

images

10. If O lies on the in-circle, prove that cos A + cosB + cos C = images2.

11. If OH makes an angle ϕ with BC, prove that

 

images

12. Prove that

 

images

13. Prove that ρ2 = (r + 2R)2s2.

14. If the circumcircle cuts the nine-point circle orthogonally prove that cos A cos B cos C = – images.

15. If AH = r, prove that the circumcircle cuts one escribed circle orthogonally.

16. If OI cuts AD at T, prove OT = OI cosimagescosec images.

17. Prove that the area of Δ OIH is

 

images

18. If S is the circumcentre of Δ BHC, prove that

 

images

19. If IO = IH, prove that either AO = AH or A, O, I, H are concyclic. Deduce that an angle of the triangle is 60°.

20. Prove NI + NI1 + NI2 + NI3 = 6R.

21. If images BAC is obtuse and if HA cuts the circumcircle at T, prove that (i) HT = 2HD ; (ii) HA . HT = 2ρ2. Hence show that

 

images

22. Prove that

(i) OI2 + OI12 + OI22 + OI32 = 12R2 ;

(ii) NA2 + NB2 + NC2 + NH2 = 3R2.

23. Prove that

(i) DA2 + DB2 + DC2 + DH2 = 4R2 ;

(ii) AI12 + AI22 + AI32 + AI2 = 16R2.

24. Prove that HA2 + HB2 + HC2 – HO2 = 3R2.

25. Prove that AG2 + BG2 + CG2 = imagesR2 (1 + cos A cos B cos C).

26. Prove that a . IA2 + b . IB2 + c . IC2 = 4Rrs;   find a similar expression for a . I3A2 + b. I3B2c . I3C2.

27. If T is any point, prove that

TA2 . sin 2A +TB2 . sin 2B +TC2. sin 2C = 4 (R2 + OT2) sin A sin B sin C.

28. If T is a point on the in-circle, prove that

 

images

29. Prove that the common chord of the circumcircle and the escribed circle, centre I1, is images.

30. If t1, t2, t3 are the lengths of the tangents from I1, I2, I3 to the circumcircle, prove that (i) images (ii) images.

Solution of Triangles from Miscellaneous Data. No general rules can be given, but the following typical examples may be useful.

(i) Given a, b – c, A.

In Fig. 15, cut off AK = AB ; then KC = bc.

 

images

FIG. 15.

Also images BKC = 90° + imagesA and images KBC = images(B – C);

 

images

This determines images(B – C) and therefore B, C.

(ii) Given a, R, Δ.

A is given by the relation images.

Also,   cos (B – C) + cos A = 2 sin B sin C = images.

This determines (B – C) and therefore B and C since A has been found.

(iii) Given the altitudes p1, p2, p3.

The ratios a: b: c are given by 2Δ = ap1 = bp2 = cp3.

A is then given by images; also c = p2 cosec A.

(iv) Given r1; r2, r3.

 

images

EXERCISE I. e.

1. Given ab = 19·8, c = 22·2, C = 29° 16′, find B.

2. Given b = 3·36, a + c = 9·28, B = 37° 25′, find A.

3. Given AD = 6, BE = 8, CF = 9, find A and a.

4. Given b = 8, c = 10, AX = 7, find A.

5. Given A = 45°, a = 2 (bc), find B.

6. Given r = 5, r1 = 12, r2 = 20, find a, c.

7. Given b, B and that a + c = 2b, show how to solve the triangle.

8. Express bc and b2 + c2 in terms of a, R, Δ.

9. Express sin imagesA in terms of r1, r2, r3.

10. Express tan B in terms of b, c, A.

11. Express c in terms of a, b, A.

12. Given B, b, c2a2, show how to find C.

13. Given A = 53° and BE = 2CF, find B.

14. Given A = 42°, r = 3·5, find the least possible value of a.

15. Given a = images57, A = 60°, Δ = 2images3 find b, B.

16. Given A = 60°, bc = 4, AD = 11, find a and sin images.

17. Given cot(B – C) = 7 and BC = 5AD, find cot B.

18. Given a, s, A, show how to find B.

19. Express a in terms of r, A, p where p = AD.

Errors. If u is a known function, f(x), of x, we have, using differentials : du = f′ (x). dx. If the value of u is calculated from a measured or observed value of x, the resulting error δu in u, due to an error δx in x is given by

 

images

If u is a known function of several independent variables x, y, z, etc., then the error in u due to errors in the values of x, y, z, etc., is given by

 

images

Example 8. The area of Δ ABC is calculated from measurements of B, C, a; find the error in the calculated value of Δ due to an error δB in the measured value of B.

 

images

Here, δB is measured in radians; thus an error of 1′ in B causes an error of approximately images in Δ.

If there are errors δB, δC, δa in B, C, a, the resulting error in Δ is given by

 

images

EXERCISE I. f.

1. If Δ is expressed as a function of a, B, C, prove that images.

2. If Δ is expressed as a function of a, b, c, prove that

 

images

3. If A is calculated from measurements of a, b, c, prove that the error due to a small error y in b is about images radians.

4. If R is calculated from measurements of a, b, c, prove that the error due to a small error x in a is about imagesx cosec A cot B cot C.

5. The base AB of a triangle ABC is fixed and the vertex C moves along the arc of a circle of which AB is a chord, prove that

 

images

6. An observer, on the ground, 50 ft. from a vertical tower, observes the angles of elevation of two marks on the tower to be 45° and 30°. Find the approximate error to which the calculated distance between them is liable if there may be an error of 1′ in each observed angle.

7. If c is calculated from measurements of a, b, C, prove that the error due to small errors x, y, γ in a, b, C is about

 

images

8. With the data of No. 7, prove that the relative error images in the calculated area of the triangle is approximately images.

9. If C is calculated from measurements of a, b, c in which there are small errors x, y, z, prove that the error in C is approximately imagescosec B – imagescot B – imagescot A.

10. If c is calculated from measurements of a, b, R and if there is a small error x in a, prove that the error in c is approximately

 

images

11. The area Δ of a triangle on a given base c is expressed in terms of c, A, B. Prove that

 

images

In finding the vertex when the base is accurately known and the base angles are subject to small errors ±α, ±β, show that the area of the small region within which the vertex must lie is approximately

 

images

12. The area ABC was calculated from the measured values a, b, 90° of BC, CA, ACB and it was found that the calculated area was too great by z and that ax, by were the true lengths of BC, CA. Show that the error in C was about images degrees, if z, x, y were small.

MISCELLANEOUS EXAMPLES

EXERCISE I. g.

1. If a + b = 2c, prove that cotimages + cot images = 2 cot images .

2. Prove that ∑(ab sin2 C) = 2s . ∑(a cos B cos C).

3. Prove that 2aR sin (B – C) = b2c2.

4. Prove that Δ = r2 cot images cot images cot images.

5. Prove that (r1r) cot2 = r2 + r3.

6. Prove that a2 = (r1r) (4R – r1 + r).

7. Prove that IA . II1 = 4Rr.

8. Prove that images.

9. Prove that the circumradius of Δ IBC is 2R sinimages and find that of Δ I1BC.

10. Prove that images.

11. Prove that images.

12. Prove that AD cuts the in-circle at an angle

 

images

13. Given images, prove that the triangle is right-angled.

14. If B = 18°, C = 36°, prove that a – b = R.

15. If cos A + cos B = images, prove that 2r – R = 2R cos C.

16. Given a, b, B, find the difference between the in-radii of the two triangles.

17. Prove that ∑(a3cos A) = abc (1 + 4 cos A cos B cos C).

18. Prove that rl, r2, r3 are the roots of

 

images

19. Prove that images.

20. If T is the mid-point of EF, prove that XT = imagesasin A.

21. If a2 cos2 A + b2 cos2 B = c2 cos2 C, prove that one of the angles A, B, C is determinate, and find it.

22. If images CAX = 90°, prove that 3accos A cos C = 2(c2a2).

23. If a, b, c are in A.P., prove that

 

images

24. ABC, ABD are equilateral triangles in perpendicular planes ; calculate images CAD.

25. If B = C = 2A, prove that images.

26. If DT, DT′ are perpendicular to AB, AC, prove that images.

27. Prove that the tangents at A, B, C to the circumcircle form a triangle of area ±R2 tan A tan B tan C.

28. Prove that the radii of the circles which touch AB, AC and the circumcircle are r sec2images and r1 sec2images. [Use Inversion.]

29. If l, m are the directed lengths of the perpendiculars from A, B to any line through C, prove that

 

images

[If A and B are on opposite sides of the line, l and m must be regarded as opposite in sign.

30. Prove that, if a > b > c, the length of the shortest line which bisects the area of ABC Is images(2Δ tan imagesC).

31. If the angles of a triangle are calculated from measured values of the sides > show that the small errors satisfy

 

images

32. If r is calculated from measured values of a, b, c, show that the error due to an error x in a is

 

images