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The denominator stays the same. Add the numerators.
or:
The denominator 4 is already a multiple of the denominator 2. Because only one of the fractions needs to change, use the traditional method to solve this one.
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This time, the 3 and the 8 don’t share any factors, so the double-cross is the best way to proceed.
Here is the traditional approach:
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The denominators of the two fractions are the same, but the numerator 5
is greater, so
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The numerators of the two fractions are the same, but the denominator of
is smaller, so
. Alternatively, you could double-cross.
39 is greater than 30, so is the greater fraction.
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The denominator 6 goes into 11 just once, so the quotient is 1 and the remainder is 11 − 6 = 5. Alternatively, split the numerator into two parts.
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Think of multiples of 11. How close can you get to 100 without going over? 11 × 9 = 99, with 1 left over.
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The shortcut is . Here’s the full path:
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The shortcut is . The full path is:
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When a factor in the numerator cancels to 1, do still write it down; in this problem, the numerator simplifies to 1. It’s safe to ignore a 1 only when a factor in the denominator cancels to 1.