Let's do the CPT for connector 1:
|
The dog barks |
The dog doesn't bark |
Aggregate |
It rains |
10 |
4 |
14 |
It doesn't rain |
8 |
5 |
13 |
Aggregate |
18 |
9 |
27 |
Here, we are talking about the following scenarios:
- Probability (Dog barks|It rains) = 10/14
- Probability (Dog doesn't bark | It rain) = 4/14
- Probability (Dog barks | It doesn't rain) = 8/13
- Probability (Dog doesn't bark | It doesn't rain) = 5/13
|
The dog barks |
The dog doesn't bark |
It rains |
10/14 |
4/14 |
It doesn't rain |
8/13 |
5/13 |
The following diagram shows the probabilities in detail:
Let's say if the probability of rain = P(rain) =0.6 then the probability of no rain = P(no rain) = 0.4.
Let's say that the CPT for the man skipping work is as follows:
|
The man skips work |
The man doesn't skip work |
The dog barks |
0.8 |
0.2 |
The dog doesn't bark |
0.3 |
0.7 |
And now, we are supposed to find out the probability of the man skipping work and the dog barks but it doesn't rain = P (Man skips work, the dog barks, it doesn't rain):
= P (Man skips work|the dog barks) *P (the dog barks|it doesn't rain) *P(it doesn't rain)
=0.8 * (8/13) *0.4
=0.1969