The GMAT often uses scenarios involving multi-part journeys in order to ask questions about “average rates.” In such cases, the test makers will give you information that includes two or more different rates or speeds. So far in this chapter, you’ve learned about both averages and rates, so it’s understandably tempting in this situation simply to average the different individual rates you’re given.
Don’t fall for this trap. Just as you cannot use the averages of two different portions of a group to determine the group’s overall average (unless you know the weights of the portions), you also cannot find the average speed of a journey from the speeds of two parts unless you know the proportion of time spent or distance traveled in those parts. The GMAT’s biggest trap with multi-part journeys or tasks is to offer an answer choice that fails to account for the weighting of the averages and simply splits the difference between the two portions. The GMAT writes its problems so that this is never the correct solution. Instead, you’ll need to use the average rate formula.
Average A per B =
Example: John travels 30 miles in 2 hours and then 60 miles in 3 hours. What is his average speed in miles per hour?
Average miles per hour =
Notice how you can check your work on this question by applying some Critical Thinking: John’s first rate was 15 miles per hour, and his second rate was 20 miles per hour, so his average rate will fall somewhere between 15 and 20 miles per hour. You can estimate effectively on this question, as on most average rate questions, by identifying the rate at which John spent longer traveling. In this case, John spent more time traveling at 20 miles per hour, so his average rate should be closer to 20 than to 15. Indeed, 18 miles per hour is consistent with the direction in which the average rate should be weighted.
Average rate problems on the GMAT can become quite complex. If your paraphrase of the question stem is anything like “First this person moves at one speed, then at another,” then you’re dealing with a multi-part journey problem. There is frequently a lot of information to deal with.
To organize the data on complicated multi-part journey problems, try jotting down this chart on your noteboard:
|
Rate |
Time |
Distance |
Part 1 of trip |
|
|
|
Part 2 of trip |
|
|
|
Entire trip |
This chart folds many equations into one:
Average speed =
Let’s go through a sample question, and you’ll see how the chart helps you.
A powerboat crosses a lake at 18 miles per hour and returns at 12 miles per hour. If the time taken turning the boat around was negligible and it returns by the same route, then what was the boat’s average speed for the round trip, in miles per hour?
When you notice that you have a multi-part journey problem, jot down the chart, using a question mark to indicate the value that the question asks you for:
|
Rate (mph) |
Time (hr) |
Distance (miles) |
Part 1 of trip |
|
|
|
Part 2 of trip |
|
|
|
Entire trip |
? |
|
|
Now fill in the data given by the problem:
|
Rate (mph) |
Time (hr) |
Distance (miles) |
Part 1 of trip |
18 |
|
|
Part 2 of trip |
12 |
|
|
Entire trip |
? |
|
|
Now you clearly have to get some information about either the time or the distance to be able to solve for much of anything. The only other piece of information you have is that the boat traveled the same route both times. That means the distance must have been the same. You could use the variable D, but the math will get fairly complicated if you do. Instead, keep it simple and pick numbers. A number that’s a multiple both of 18 and of 12 will make the math work out nicely, so let’s say the lake was 36 miles across:
|
Rate (mph) |
Time (hr) |
Distance (miles) |
Part 1 of trip |
18 |
|
36 |
Part 2 of trip |
12 |
|
36 |
Entire trip |
? |
|
|
Now you can solve for the times and the total distance:
|
Rate (mph) |
Time (hr) |
Distance (miles) |
Part 1 of trip |
18 |
2 |
36 |
Part 2 of trip |
12 |
3 |
36 |
Entire trip |
? |
|
72 |
And finally for total time:
|
Rate (mph) |
Time (hr) |
Distance (miles) |
Part 1 of trip |
18 |
2 |
36 |
Part 2 of trip |
12 |
3 |
36 |
Entire trip |
? |
5 |
72 |
Now you have what you need to solve for average rate. It’s mph. This answer makes logical sense, since the two rates are 18 and 12 miles per hour and the boat spent more time traveling at the lower speed, so the average is closer to 12 than to 18.
Now let’s use the Kaplan Method on a Data Sufficiency question dealing with a multi-part journey:
This is a Value question, so you need one exact speed for the trip from Point X to Point Z.
Use Critical Thinking: there’s no direct simplification to be done, but since you can sometimes calculate exact speeds with unknown distance or time, there might be a way to solve for speed without knowing the exact distance and time.
To answer the question, you’ll need either the exact distance and time or some information about distance or time that allows you to calculate speed.
Statement (1) gives you some data about the trip from X to Y but nothing about X to Z. Insufficient. Eliminate (A) and (D). Likewise, Statement (2) gives you data about the trip from Y to Z but nothing about X to Z. Insufficient. Eliminate (B).
Now you must combine. Notice that something crucial is missing—information relating either the times or the distances of the X-to-Y and the Y-to-Z leg. If the X-to-Y distance were 10 miles and the Y-to-Z distance were 10 inches, the average speed would be essentially 10 mph. And if it’s the other way around, with the X-to-Y distance 10 inches and the Y-to-Z distance 10 miles, the average speed would be essentially 8 mph. The combined statements are insufficient, so the answer is (E).