Polygons

A polygon is a closed figure whose sides are straight line segments.

The perimeter of a polygon is the distance around the polygon, or the sum of the lengths of the sides.

A vertex of a polygon is the point where two adjacent sides meet.

A diagonal of a polygon is a line segment connecting two nonadjacent vertices.

A regular polygon has sides of equal length and interior angles of equal measure.

The number of sides determines the specific name of the polygon. A triangle has three sides, a quadrilateral has four sides, a pentagon has five sides, and a hexagon has six sides. Triangles and quadrilaterals are by far the most important polygons on the GMAT.

Interior and Exterior Angles

A polygon can be divided into triangles by drawing diagonals from a given vertex to all other nonadjacent vertices. For instance, the pentagon below can be divided into three triangles. Since the sum of the interior angles of each triangle is 180°, the sum of the interior angles of a pentagon is 3 × 180° = 540°.

Pentagon PQRST.  Dotted line segments RP and RT in the interior of the pentagon form 3 triangles.

Example:

An unlabeled hexagon with three interior dotted line segments that form 4 triangles. 

What is the measure of one interior angle of the regular hexagon above?

You need to find the sum of the interior angles and divide by the number of interior angles, or 6. Since the hexagon is regular, all angles are equal, so each of them is equal to one-sixth of the sum. Since you can draw four triangles in a six-sided figure, the sum of the interior angles will be 4 × 180°, or 720°. Therefore, each of the six interior angles measures or 120 degrees.

While splitting up polygons into triangles always works to find the sum of the interior angles, there is a formula you can memorize to speed up the process. The sum of the interior angle measures of a polygon with n sides is equal to (n − 2)180°. Therefore, in a regular polygon, the measure of each interior angle can be calculated using this formula: .

Quadrilaterals

The most important quadrilaterals to know for the GMAT are the rectangle and square. Anything could show up on the test, but concentrate on the most important figures and principles. The lesser-known properties can readily be deduced from the way the figure looks and from your knowledge of geometry.

Quadrilateral

A quadrilateral is a four-sided polygon. The sum of its four interior angles is 360°.

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Rectangle

A rectangle is a quadrilateral with four equal angles, each a right angle.

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The opposite sides of a rectangle are equal in length. Also, the diagonals of a rectangle have equal length and bisect each other.

Square

A square is a rectangle with four equal sides.

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Areas of Quadrilaterals

To find the area of a rectangle, you multiply the lengths of any two adjacent sides, called the length and width.

Area of a rectangle = length × width = lw.

To find the area of a square, since length and width are equal, you say:

Area of a square = (side)2 = s2.

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In the rare event that you have to find the area of a parallelogram (a quadrilateral with equal and parallel opposite sides), multiply the base and the height.

Area of a parallelogram = base × height = bh.

A parallelogram with labeled base and height.  The height meets the base at a 90 degree angle.

The diagonals of a parallelogram do not necessarily have equal length, but they do bisect each other.

The area of a trapezoid—a quadrilateral with exactly one pair of parallel sides—can be calculated as follows:

Area of a trapezoid = (the sum of the bases)(height) = (b1 + b2)(h).

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In-Format Question: Polygons on the GMAT

Now let’s use the Kaplan Method on a Problem Solving question dealing with polygons:

  1. A quadrilateral with sides measuring 10, 10, 16, and an unlabeled side.  The sides measuring 16 and 10 both meet the unlabeled side at 90 degrees.  The other side measuring 10 degrees meets the sides measuring 10 and 16 at non-90 degree angles.
    What is the perimeter of the figure above?
    1. 43
    2. 44
    3. 46
    4. 47
    5. 48

Step 1: Analyze the Question

If this were a simple square or triangle, your work would be quick. However, when given an unfamiliar shape on the GMAT, you can often split the figure into smaller, familiar shapes to calculate the needed sides or angles.

Step 2: State the Task

The task is to solve for the perimeter of the figure, or the sum of the length of its sides. To do this, you need to determine the length of the unlabeled side.

Step 3: Approach Strategically

Pattern Recognition helps you recognize that this polygon can be broken down into smaller, more manageable figures. In this case, you can break the shape into a rectangle and a right triangle. Drop a perpendicular from the left endpoint of the top horizontal side of length 10 to the bottom horizontal side of length 16.

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This perpendicular will divide the quadrilateral into a right triangle and a rectangle. Because the lengths of the opposite sides of a rectangle are equal, the horizontal sides of the rectangle both have a length of 10. This means that the horizontal leg of the right triangle will have a length of 16 − 10, or 6.

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At this point you might recognize that the right triangle is a special right triangle. It is a 3:4:5 right triangle, and each side of it is a member of the 3 to 4 to 5 ratio multiplied by 2. The leg of length 6 is 2 × 3, and the hypotenuse of length 10 is 2 × 5. So the length of the other leg is 2 × 4 = 8. Because opposite sides of a rectangle are equal, the vertical side of the rectangle at the right also has a length of 8.

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Now you can find the perimeter of the quadrilateral. The sum of the length of the figure’s sides is 16 + 10 + 10 + 8 = 44. That’s choice (B).

If you were short on time for this question, you could use Critical Thinking to strategically eliminate a few of the answer choices. In any right triangle, the hypotenuse is always the longest side of the triangle. So in the figure, the side shared by the triangle and rectangle must be less than 10, since it makes up one of the legs of the right triangle.

If the short side of the rectangle were equal to 10, then the perimeter of the total quadrilateral would be 10 + 10 + 10 + 16 = 46. Since you know that one of the sides must be less than 10, the perimeter must be less than 46. This definitively eliminates (C), (D), and (E), and you have a much better chance of picking the correct answer.

Step 4: Confirm Your Answer

Read back over the problem, confirming that your solution accurately follows the information in the question.

Practice Set: Polygons on the GMAT

  1. A frame 2 inches wide is placed around a rectangular picture with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches?
    1. 44
    2. 96
    3. 128
    4. 144
    5. 168
  2. A square occupies one corner of a larger rectangle. The sides of the rectangle are 4 and 10 meters longer than the sides of the square.
    A square garden with an area of 36 square meters is enlarged into a rectangular garden, as shown in the figure above. What is the perimeter of the additional section of the garden, in meters?
    1. 40
    2. 52
    3. 56
    4. 124
    5. 160
  3. Is the length of a side of square S greater than the length of a side of equilateral triangle T?
    1. The sum of the lengths of a side of S and a side of T is 22.
    2. The ratio of the perimeter of square S to the perimeter of triangle T is 5 to 6.