The slope of a line on a coordinate plane tells you how steeply that line goes up or down. If a line gets higher as you move to the right, it has a positive slope. If it goes down as you move to the right, it has a negative slope. To find the slope of a line, use the following formula:
Rise means the difference between the y-coordinate values of the two points on the line, and run means the difference between the x-coordinate values.
Example: What is the slope of the line that contains the points (1,2) and (4,−5)?
To determine the slope of a line from an equation, put the equation into slope-intercept form: y = mx + b, where the slope is m.
Example: What is the slope of the line given by the equation 3x + 2y = 4?
The word intercept in “slope-intercept form” is there because b is the value of the y-intercept—the point at which the line crosses the y-axis. Another way to think of that is that (0,b) will be a point on the line.
Perpendicular lines have slopes that are negative reciprocals of one another. For the line in this example, with a slope of , a perpendicular line would have a slope of .
To determine the distance between any two points on a coordinate plane, you can use the Pythagorean theorem.
Example: What is the length of AB?
Sketch lines from points A and B parallel to the axes. They will form a right triangle, and the intersection will have the same x-coordinate as one point and the same y-coordinate as the other. Because the new lines aren’t diagonal, their length is easy to figure out. In this example, the length of AC is 7 because the line drops down 5 from A to the x-axis and then another 2 to C. Similarly, the length of BC is 6.
Now you can use the Pythagorean theorem to calculate AB:
Now let’s use the Kaplan Method on a Data Sufficiency question dealing with coordinate geometry:
In this Value question, you are asked to determine which quadrant the point (s, t) is in. You are told in the question stem that st > 0, which means that s and t are either both positive or both negative. This is only true in quadrants I and III.
Statement (1): You know that (s,−t) lies in quadrant II, which tells you that s is negative and −t is positive, so t must be negative. Because s and t are both negative, (s,t) is in quadrant III, and the statement is sufficient. Eliminate (B), (C), and (E).
Statement (2): You are told that s is negative, which is also sufficient, because you already deduced from the question stem that s and t have the same sign.
The correct answer is (D).
Line is given by the equation y = mx + 3, and line is given by the equation y = nx − 7; m and n are constants. Is parallel to ?