Chapter 18
IN THIS CHAPTER
Taking off on the coordinate plane
Using formulas to find slope, graph lines, and determine midpoints and distances
Evaluating functions
Coordinate geometry involves working with points on a graph that’s officially known as the Cartesian coordinate plane. This perfectly flat surface has a system that allows you to identify the position of points by using pairs of numbers. In this chapter, you figure out how equations and numbers relate to geometric forms and shapes, such as a straight line or a parabola, and review the formulas you need to know to fly high on questions about the coordinate plane.
The coordinate plane doesn’t have wings, but it does have points that spread out infinitely. You may not have encountered the coordinate plane in a while (it isn’t something most people deal with in everyday life), so take just a minute to refresh your memory about a few relevant terms that may pop up on the GMAT. Although you won’t be asked to define the terms in the following sections, knowing what they mean is absolutely essential to answering GMAT math questions.
Before you get too engrossed in the study of coordinate geometry, ground yourself with an understanding of these essential terms:
You can identify any point on the coordinate plane by its coordinates, which designate the point’s location along the x- and y-axes. For example, the ordered pair (2, 3) has a coordinate point located two units to the right of the origin along the horizontal (x) number line and three units up on the vertical (y) number line. In Figure 18-1, point A is at (2, 3). The x-coordinate appears first, and the y-coordinate shows up second. Pretty simple so far, huh?
The intersection of the x- and y-axes forms four quadrants on the coordinate plane, which just so happen to be named Quadrants I, II, III, and IV (see Figure 18-1). Here’s what you can assume about points based on the quadrants they’re in:
Quadrant I starts to the right of the y-axis and above the x-axis. It’s the upper-right portion of the coordinate plane. As shown in Figure 18-1, the other quadrants move counterclockwise around the origin. Figure 18-1 also shows the location of coordinate points A, B, C, and D:
The GMAT won’t ask you to pick your favorite quadrant, but you may be asked to identify which quadrant a particular point belongs in.
One of the handiest things about the coordinate plane is that it graphs the locations of lines and linear equations. In fact, questions that expect you to know how to graph lines and equations are some of the most common GMAT coordinate geometry questions. You should know the formulas for finding the slope and the slope-intercept equation and for determining the midpoint and the distance between two points on the plane. Lucky for you, we discuss all those formulas in the following sections.
If a line isn’t parallel to one of the coordinate axes, it either rises or falls from the left-hand side of the coordinate plane to the right-hand side. The measure of the steepness of the line’s rising or falling is its slope. In the following sections, we explain how to find the slope of a line and explore the different types of slopes on a coordinate plane.
You can think of the slope as the value of the rise over the value of the run. In more mathematical terms, the slope formula looks like this:
The x and y values in the equation stand for the coordinates of two points on the line. The formula is just the ratio of the vertical distance between two points and the horizontal distance between those same two points. You subtract the y-coordinate of one point from the y-coordinate of the other point to get the numerator. Then you subtract the x-coordinate of one point from the x-coordinate of the other point to get the denominator.
The graph in Figure 18-2 shows how important it is to perform these operations in the right order.
Figure 18-2 shows coordinate point (0, 2) as , and the coordinate point (4, 0) as . You may be tempted to subtract the 0 in each coordinate point from the corresponding greater number in the other coordinate point, but doing that switches the order of how you subtract the x and y values in the two coordinate points.
For the slope formula to work, you calculate for your operation (which gives you –2), and then you take for your (which gives you 4). The resulting ratio, or fraction, is , or . This gives you a slope of .
The line in Figure 18-2 falls from left to right. This nice ski-slope image is your visual clue that the line has a negative slope. Figure 18-3 shows how you can quickly eyeball a line to get a good idea of what kind of slope the line has.
In Figure 18-3, line m has a negative slope; line n has a positive slope; a line on the horizontal x-axis has a slope of 0; and a line on the vertical y-axis has an undefined slope.
The characteristics of a line can be conveyed through a mathematical formula. The equation of a line (also known as the slope-intercept form) generally shows y as a function of x, like this:
In the slope-intercept form, the coefficient m is a constant that indicates the slope of the line, and the constant b is the y-intercept (that is, the point where the line crosses the y-axis). The equation of the line in Figure 18-2 is , because the slope is and the y-intercept is 2. The equation indicates a horizontal line that intersects the y-axis at point (0, 2). The equation indicates a vertical line that intersects the x-axis at point (3, 0). A line with the formula has a slope of 4 (which is a rise of 4 and run of 1) and a y-intercept of 1. The line is graphed in Figure 18-4.
The GMAT may give you an equation of a line and ask you to choose the graph that correctly grids it. You can figure out how the line should look when it’s graphed by starting with the value of the y-intercept, marking points that fit the value of the slope, and then connecting these points with a line.
The new equation gives you the slope of the line, 3, as well as the y-intercept, 9. Pretty handy! Here’s a sample question to give you a taste of how the slope-intercept form may be tested on the GMAT.
What is the equation of a line with a slope and a y-intercept of 8?
(A)
(B)
(C)
(D)
(E)
In the slope-intercept form, , m is the slope, and b is the y-intercept. Plug the values the problem gives you into the equation:
This isn’t an answer choice, but all options have the same format of . So you need to convert your equation to that format. Move the terms around by multiplying all terms on both sides by 4 and adding 3x to both sides, like this:
Choice (E) is the correct answer.
Graphing a linear inequality is almost exactly the same as graphing the equation of a line, except a linear inequality covers a lot more ground on the coordinate plane. While the graph of an equation for a line simply shows the actual line on the coordinate plane, the graph of a linear inequality shows everything either above or below the line on the plane. The graph appears as a shaded area to one side of the line. Figure 18-5 shows the graphs of several inequalities.
If the GMAT asks you for the midpoint coordinates of a line segment on the coordinate plane, you simply apply the midpoint formula:
M stands for midpoint and the x and y variables are the x and y coordinates of the line’s two endpoints. So, to figure out the midpoint of a line segment that ends at points A (2, 3) and B (–1, 4), use the formula:
Some of the questions on the GMAT may ask you to calculate the distance between two points on a line. You can solve these problems with coordinate geometry.
To answer these questions, use the distance formula. Assume you have two points, A and B , on a line. The formula to find the distance between A and B is this:
Look at the graph in Figure 18-6 to see how the distance formula actually works.
Notice that Point A has coordinates (2, 1) and Point B has coordinates (6, 4). To find the distance between these two points, you plug these numbers into the distance formula:
If you’re thinking this formula looks familiar, you’re absolutely right. It’s another use for the good old Pythagorean theorem: . (If this theorem is only vaguely familiar to you, check out Chapter 17.) Connecting points A and B to a third point, C, as shown in Figure 18-5, gives you a right triangle, which in this case happens to be your tried-and-true 3:4:5 right triangle.
Here’s a sample problem that asks you to find the distance between two points.
What is the distance in units of a line segment that connects the origin to the coordinate point (–2, –3)?
(A)
(B)
(C) 5
(D) 8.94
(E) 13.42
Use the distance formula to figure out the distance between the coordinates of the origin (0, 0) and the endpoint (–2, –3):
Choice (B) is the answer. If you chose Choice (C), you simply took the coordinates for the endpoint, (–2, –3), and added them together to get distance, which, of course, isn’t the proper method. Choice (A) results from failing to square the differences of the coordinates. You can guess that Choices (D) and (E) are probably incorrect because uncovering their values requires using a calculator, which you won’t have available on the GMAT quantitative section.
Occasionally, the GMAT may ask you coordinate geometry questions that deal with shapes other than straight lines.
Parabolas: When you graph a quadratic equation, it appears as a parabola, a curve shape that opens either upward or downward. Two important properties of parabolas are
The equation for a parabola is , where the coordinate point (h, k) is the vertex. The vertical line x = h is the axis of symmetry. If a is a positive number, the parabola opens upward. If a is negative, it opens downward. Figure 18-7 shows the graph of . The values for h and k are 0, so the vertex is at the origin. The parabola opens upward because a is 1, a positive number.
Here’s a sample question that requires to you apply the parabola formula.
What is the vertex of the graph of the equation ?
(A) (–3, –4)
(B) (3, 4)
(C) (3, –4)
(D) (–3, 4)
(E) (–6, –4)
Remember the equation of a parabola: . The vertex of the parabola is (h, k). The h value in the equation is 3, and the k value is –4. So the vertex of the graph of the equation in the question is (3, –4). The correct answer is Choice (C).
Choice (D) is a trap answer. Note that the value of h is 3 and not –3. The only way that the value of h could be –3 is if the original equation were . Then you’d have to switch the sign to put the equation into the correct form for the equation of a parabola.
Coordinate geometry and functions are connected. You can actually evaluate functions on the coordinate plane. By looking at a graph of a function, you can tell something about the function and its domain and range. The GMAT may give you a graph of a function and ask you to determine whether a statement about the function is true or false. In the following sections, we give you the info you need to know to get these questions right.
When you graph a function f(x) on the coordinate plane, the x value of the function (the input, or the domain, of the function) goes along the horizontal (x) axis, and the f(x) value of the function goes along the vertical (y) axis. Anytime you see a coordinate pair that represents a function, for example (x, y), the x value is the domain, or input, of the function and the y value is the output, or range, of the function. (For more info on functions, see Chapter 16.)
A function is a distinct relationship between the x (input) value and the y or f(x) (output) value. For every x value, there’s a distinct y value, and only one y value, that corresponds to the x value. The vertical line test is one way to look at a graph and tell whether it’s a graph of a function. This test states that no vertical line intersects the graph of a function at more than one point.
For example, the graphs in Figure 18-8 show two straight lines that pass the vertical line test and, therefore, represent functions.
The two lines in Figure 18-8 go on infinitely in both directions. Any vertical line you draw on the graph intersects the graphed line at only one point. For every x value along the line in each of these graphs, a separate and distinct y value corresponds to it. These lines pass the vertical line test, which means they represent functions.
Not all lines are straight. Sometimes you see graphs of curved lines. Take a look at the two graphs in Figure 18-9 and determine which of them graphs a function.
The curves in Figure 18-9 are parabolas, a shape we discuss in more detail in the upcoming section about graphing domain and range. The curve in the left graph opens downward, so it goes on infinitely downward and outward. For every x value on that curve, there’s a separate and distinct y value. This curve passes the vertical line test and, therefore, graphs a function. The curve in the right graph is almost like the first one, except that it opens sideways. One vertical line can cross the path of this curve in more than one place. Therefore, this curve isn’t the graph of a function.
Questions that ask you to recognize the graph of a function appear rarely on the GMAT, but if you see one, you’ll know what to do.
Which of the following graphs is not a graph of a function?
This question is easy when you’re familiar with the vertical line test. Choice (E) has to be the correct answer because it’s a curve that sort of doubles back from right to left. A vertical line can intersect that curve at more than one point. The other graphs in this question show curves, lines, or some other shape that a vertical line wouldn’t pass through at more than one point. All the graphs except Choice (E) pass the test and are graphs of functions.
The GMAT expects you to be able to look at a graph of a function and have a pretty good idea of what the domain and the range of that particular function are. Figures 18-10, 18-11, and 18-12 are examples of what some of these graphs may look like.
Figure 18-10 shows you a parabola. Its vertex is the coordinate point (0, 2). The graph extends outward infinitely from side to side, so this function contains all possible values of x, which means its domain is all real numbers. The graph also extends downward infinitely, but because the y value in this function is limited on the upward side and doesn’t extend above the point (0, 2), its range is .
In Figure 18-11, you see a straight line that goes on forever from left to right. This line also extends infinitely upward on the left side and infinitely downward on the right side. The domain and range of this linear function are also all real numbers. There’s no artificial limit to the x and y values in this graph.
In Figure 18-12, the horizontal line extends infinitely from right to left, but it has only one value on the y-axis. Its y value is limited to –3, so the equation for this line is , and the range is limited to simply . Because the line goes on forever from left to right, it includes every possible x value, which means the domain of this linear function is all real numbers.
That’s really all there is to it. See how easy determining domain can be with the following question.
Which of the following answers could be the domain of the function of the figure?
(A)
(B)
(C)
(D)
(E)
This question asks for the domain, not the range, so don’t let the fact that the upper limit of the y value is just shy of 3 distract you from looking for all the possible x values that make up the domain. You should toss out any answer choice that refers to the value 3, so get rid of Choices (B) and (D) right away.
The empty circle point (0, 3) means that you don’t count that point in your answer. So Choice (C) is exactly the opposite of what you’re looking for. Also, Choice (C) limits your domain to only one value: 0. Because the value of 0 is actually excluded from the function, Choice (C) simply can’t be right. The way Choice (E) is formatted doesn’t make sense at all. Set your sights on Choice (A) as the answer of the hour. The domain, or x value, isn’t equal to 0.