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√1
√1+ √1
X=3
log {base 16} (4)=x
V=VX
|-4+10|
ّ±7
(16 x 1)/2
32
f(x)=10
121½
X-6, where X=18
44÷4 + √4
28(½)
50% of 30
42
(5x4)-½(9)
(24-20) x 9 -18
(3 * 5) + 12² / 12 - 8
(2+2+2+2+2) x 2
|{7X-3}|
22°
XXIII
...∞...
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