Chapter 4

Algebra

It isn’t what people think that’s important, but the reason they think what they think.

—Eugène Ionesco

4.1: Monomial

Definition: Any number or variable or product of numbers and variables.

Examples: 3, -4x, xy3, 1.5xy2a3b4

Problem 37

Find the product

(3a2b3)(–2a5b2)

 

Solution 37

(3a2b3)(–2a5b2) = –6a7b5

Remember your exponential formulas/rules:

ab × ac = ab+c
(ab)c = abc
ab/ac = ab–c

4.2: Coefficient

Definition: The number that appears in front of the variable(s).

Example: Given monomials 2a; -3xy; and 17x2yz5, their corresponding coefficients are 2, -3, and 17.

Problem 38

Calculate the coefficient of

2a × (–3xy) × 17x2yz5

 

Solution 38

The resulting monomial is:

–102ax3y2z5

and its coefficient is –102.

4.3: Polynomial

Definition: A polynomial is the sum of two or more monomials.

Example: xy3 + 1.5xy2a3b4

Problem 39

Find the product

–5b(2b5 + 7b3 – 9b)

 

Solution 39

 –5b(2b5 + 7b3 – 9b) =

              –5b(2b5) – 5b(7b3) – 5b(–9b) =

–10b6 – 35b4 + 45b2

4.4: Term

Definition: The term (of a polynomial) is each monomial that makes up the polynomial (i.e., a number, a variable, or a product of a number and a variable or variables).

Example:

binomials = polynomials with two terms (e.g., 5x – 10)
trinomials = polynomials with three terms (e.g., 7x3 + 2x – 4)

The degree of a term is the sum of the exponents on the variables contained in the term.

Problem 40

Calculate the degrees of 2ab and 5y3

 

Solution 40

The degree of the term 2ab is 1 + 1 = 2. The exponent on a is 1 and on b is 1 and the sum of the exponents is 2.

The degree of the term 5y3 would be 3 because the exponent of the only variable contained in the term is 3.

4.5: Like Terms

Definition: Terms that have exactly the same variables and exponents; they are the only terms of the polynomial that can be combined.

Example: 5a2b3 and -13a2b3

Problem 41

Calculate the coefficients a, b, c, and d such that

ax3 + bx2 + cx + d = (x – 1)(x + 1)(2x + 3)

 

Solution 41

(x – 1)(x + 1)(2x + 3) = (x2 – 1)(2x + 3) =
= 2x3 – 2x + 3x2 – 3 =
= 2x3 + 3x2 – 2x – 3

Thus,

a = 2, b = 3, c = –2, d = –3

4.6: Exponents

Definition: Exponents are shorthand for multiplication: (5)(5) = 52, (5)(5)(5) = 53. The exponent stands for however many times the number, variable, or a combination (product) of the two are being multiplied. The quantity that’s being multiplied is called the base. This process of using exponents is called “raising to a power,” where the exponent is the “power.” So, 53 is “five, raised to the third power.” When we deal with numbers, we usually just simplify; we’d rather deal with 27 than with 33. But with variables, we need the exponents, because we’d rather deal with A6 than with A × A × A × A × A × A.

Properties.

(xm)(xn) = x(m + n)

(xm)n = x mn

Any number that is not 0 raised to the power 0 is just 1. As a result,

image

Example: Write image using only positive exponents.

image

Problem 42

Given the following equation

64x – 3 = 2–3x

Calculate x.

 

Solution 42

64 = 8 × 8 = 23 × 23 = 26

Thus   (26)x – 3 = 2–3x

       26(x – 3) 2–3x

       6(x – 3) = –3x

       9x = 18

       x = 2

4.7: Function

Definition: Rule/formula describing how to associate elements that belong to two different sets (“domain” and “range,” see below); it assigns to each number in one set (domain) a number in the other set (range).

Examples:

Example 1:

image

where x = “argument” (of the function)

Example 2:

image

The graphical representation of the function y = f(x) in the xy coordinate system for the two examples above is shown below:

Example 1:

image

Example 2:

image

4.8: Quadratic Function

Definition: Polynomial function that takes the form: ax2 + bx + c where a ≠ 0 (the highest exponent of x is 2); its graph is a 2nd degree polynomial or a parabola (see graph example below).

Example:

f(x) = ax2 + bx + c = 0

Solution:image

where: f(x) = a(xx1)xx2)

The graph of a quadratic function is a parabola:

image

Problem 43

A rancher has 1200 meters of fence to enclose a rectangular corral with another fence dividing it in the middle as in the diagram below.

image

Calculate the largest possible area that can be enclosed with the available fence.

 

Solution 43

Total area: A = 2xy

In addition, x and y must satisfy.

3y + 4x = 1200
3y = 1200 – 4x
y = 400 – 4x/3

We now have y expressed as a function of x, and we can substitute this expression for y in the formula for total area A.

A = 2xy = 2x (400 – 4x/3)

We need to find the value of x that makes A as large as possible. A is a quadratic function of x, and the graph opens downward, so the highest point on the graph of A is the vertex. The graph of the function (not required to solve the problem) is shown below:

image

Since A is factored, the easiest way to find the vertex is to find the x-intercepts and average.

2x (400 – 4x/3) = 0
2x = 0 or 400 – 4x/3 = 0
x = 0 or 400 = 4x/3
x = 0 or 1200 = 4x
x
= 0 or 300 = x

Therefore, the line of symmetry of the graph of A is x = 150, the average of 0 and 300.

Now that we know the value of x corresponding to the largest area, we can find the value of y by going back to the equation relating x and y.

image

The maximum value of the area A is therefore

Amax = 2 × 150 × 200 = 60,000 [m2]

4.9: Domain

Definition: The domain of a function is the set of all of the values for which the function is defined (the x values.).

Example: The domains of the functions illustrated in the two examples in the function section above are

Example 1:

image

Domain:

x ∈(–, 0)(0,3)(3, +) or x ∈(–, +) – {0,3}

Example 2:

image

Domain:

x 7 or x ∈ [7, +)

Example #3:

f(x) = x2 – 2x + 5

image

Example #4:

image

image

Example #5:

image

image

The domains for the three functions shown above are

Function Domain
f(x) = x2 – 2x + 5 (–,+)

image

(–, 2)(2, +)

image

[–5, +)

4.10: Range

Definition: Range (of a function) is the set of all of the values that are the output (result) of applying the function (the f(x) or y values).

Example:

The range of values for f(x) corresponding to each interval on which x is defined in the graphs shown in the domain section is shown below.

Function Domain

image

image

image

[0, +)

f(x) = x2 – 2x + 5

[4, +)

Function Domain

image

(–, +)

image

[0, +)

4.11: Solving Equations/Inequalities

Systems of (linear) equations can be solved using techniques such as substitution, elimination/addition, graphing, and Gaussian elimination. The most popular ones are substitution (see p. 13) and elimination/addition (see p. 18).

In solving inequalities or systems of inequalities, most rules and properties used to solve linear equations/systems of equations are valid. A notable exception is the following:

If the signs of both sides of an inequality are changed (or both sides are multiplied by a negative number), then the sense of the inequality will change, so if

x < y
then
-x > -y

See Problems 180 and 185 for sample problems.