6

Tree-level amplitudes

We are now ready to study string interactions. In this chapter we consider the lowest order amplitudes, coming from surfaces with positive Euler number. We first describe the relevant Riemann surfaces and calculate the CFT expectation values that will be needed. We next study scattering amplitudes, first for open strings and then for closed. Along the way we introduce an important generalization in the open string theory, the Chan–Paton factors. At the end of the section we return to CFT, and discuss some general properties of expectation values.

6.1    Riemann surfaces

There are three Riemann surfaces of positive Euler number: the sphere, the disk, and the projective plane.

The sphere

The sphere S2 can be covered by two coordinate patches as shown in figure 6.1. Take the disks |z| < Image and |u| < Image for Image > 1 and join them by identifying points such that

Image

Fig. 6.1.   The sphere built from z and u coordinate patches.

Image

In fact, we may as well take Image → ∞. The coordinate z is then good everywhere except at the ‘north pole,’ u = 0. We can work mainly in the z patch except to check that things are well behaved at the north pole.

We can think of the sphere as a Riemann surface, taking the flat metric in both patches and connecting them by a conformal (coordinate plus Weyl) transformation. Or, we can think of it as a Riemannian manifold, with a globally defined metric. A general conformal gauge metric is

Image

Since dzdImage = |z|4dudImage, the condition for the metric to be nonsingular at u = 0 is that exp(2Image(z,Image)) fall as |z|−4 for z → ∞. For example,

Image

describes a sphere of radius r and curvature R = 2/r2.

According to the general discussion in section 5.2, the sphere has no moduli and six CKVs, so that in particular every metric is (diff × Weyl)-equivalent to the round metric (6.1.3). Let us see this at the infinitesimal level. As in eq. (5.2.8) one is looking for holomorphic tensor fields Imagegzz(z) and holomorphic vector fields Imagez(z). These must be defined on the whole sphere, so we need to consider the transformation to the u-patch,

Image

Any holomorphic quadratic differential Imagegzz would have to be holomorphic in z but vanish as z−4 at infinity, and so must vanish identically. A CKV Imagez, on the other hand, is holomorphic at u = 0 provided it grows no more rapidly than z2 as z → ∞. The general CKV is then

Image

with three complex or six real parameters as expected from the Riemann–Roch theorem.

These infinitesimal transformations exponentiate to give the Möbius group

Image

for complex Image, Image, Image, Image. Rescaling Image, Image, Image, Image leaves the transformation unchanged, so we can fix ImageImageImageImage = 1 and identify under an overall sign reversal of Image, Image, Image, Image. This defines the group PSL(2, C). This is the most general coordinate transformation that is holomorphic on all of S2. It is one-to-one with the point at infinity included. Three of the six parameters correspond to ordinary rotations, forming an SO(3) subgroup of PSL(2, C).

The disk

It is useful to construct the disk D2 from the sphere by identifying points under a reflection. For example, identify points z and z such that

Image

In polar coordinates z = rImageiImage, this inverts the radius and leaves the angle fixed, so the unit disk |z| ≤ 1 is a fundamental region for the identification. The points on the unit circle are fixed by the reflection, so this becomes a boundary. It is often more convenient to use the conformally equivalent reflection

Image

The upper half-plane is now a fundamental region, and the real axis is the boundary.

The CKG of the disk is the subgroup of PSL(2, C) that leaves the boundary of the disk fixed. For the reflection (6.1.8) this is just the subgroup of (6.1.6) with Image, Image, Image, Image all real, which is PSL(2, R), the Möbius group with real parameters. One CKV is the ordinary rotational symmetry of the disk. Again, all metrics are equivalent — there are no moduli.

The projective plane

The projective plane RP2 can also be obtained as a Image2 identification of the sphere. Identify points z and z with

Image

These points are diametrically opposite in the round metric (6.1.3). There are no fixed points and so no boundary in the resulting space, but the space is not oriented. One fundamental region for the identification is the unit disk |z| ≤ 1, with points ImageiImage and −ImageiImage identified. Another choice is the upper half-z-plane. There are no moduli. The CKG is the subgroup of PSL(2, C) that respects the identification (6.1.9); this is just the ordinary rotation group SO(3).

Both the disk and projective plane have been represented as the sphere with points identified under a Image2 transformation, or involution. In fact, every world-sheet can be obtained from a closed oriented world-sheet by identifying under one or two Image2s. The method of images can then be used to obtain the Green’s functions.

6.2    Scalar expectation values

The basic quantities that we need are the expectation values of products of vertex operators. In order to develop a number of useful techniques and points of view we will calculate these in three different ways: by direct path integral evaluation, by using holomorphicity properties, and later in the chapter by operator methods.

The path integral method has already been used in section 5.3 for the Faddeev–Popov determinant and in the appendix for the harmonic oscillator. Start with a generating functional

Image

for arbitrary JImage(Image). For now we work on an arbitrary compact two-dimensional surface M, and in an arbitrary spacetime dimension d. Expand X Image(Image) in terms of a complete set ImageI (Image),

Image

Then

Image

where

Image

The integrals are Gaussian except for the constant mode

Image

which has vanishing action and so gives a delta function. Carrying out the integrations leaves

Image

As discussed in section 2.1 and further in section 3.2, the timelike modes Image give rise to wrong-sign Gaussians and are defined by the contour rotation1 Image, I Image 0. The primed Green’s function excludes the zero mode contribution,

Image

It satisfies the differential equation

Image

where the completeness of the ImageI has been used. The ordinary Green’s function with a delta function source does not exist. It would correspond to the electrostatic potential of a single charge, but on a compact surface the field lines from the source have no place to go. The Image term can be thought of as a neutralizing background charge distribution.

The sphere

Specializing to the sphere, the solution to the differential equation (6.2.8) is

Image

where

Image

The constant k is determined by the property that G is orthogonal to Image0, but in any case we will see that the function Image drops out of all expectation values. It comes from the background charge, but the delta function from the zero-mode integration forces overall neutrality, Image, and the background makes no net contribution.

Now consider the path integral with a product of tachyon vertex operators,

Image

This corresponds to

Image

The amplitude (6.2.6) then becomes

Image

The constant here is

Image

The determinant can be regularized and computed, but we will not need to do this explicitly. We are employing here the simple renormalization used in section 3.6, so that the self-contractions involve

Image

Note that

Image

is finite by design. The path integral on the sphere is then

Image

The function Image has dropped out as promised. The dependence on the conformal factor Image(Image) is precisely that found in section 3.6 from the Weyl anomaly in the vertex operator. It will cancel the variation of g1/2 for an on-shell operator.2 We can take a metric that is flat in a large region containing all the vertex operators (‘pushing the curvature to infinity’) and the term in Image(Imagei) drops out.

Higher vertex operators are exponentials times derivatives of X Image, so we also need

Image

This is given by summing over all contractions, where every ImageX or ImageX must be contracted either with an exponential or with another ImageX or ImageX. The XX contraction is simply −ImageImage′ ln |z|2, the Images again dropping out in the final expression. The result can be summarized as

Image

Here

Image

come from the contractions with the exponentials. The expectation values of qImage = ImageX ImageImageImage are given by the sum over all contractions using −ImageImageImage(zz)−2 Image′ / 2, and those of Image by the conjugate.

Now we repeat the calculation in a different way, using holomorphicity. As an example consider

Image

The OPE determines this to be

Image

where g(z1, z2) is holomorphic in both variables. In the u-patch,

Image

so the condition of holomorphicity at u = 0 is that expectation values of ImagezX Image fall as z−2 at infinity. More generally, a tensor of weight (h, 0) must behave as z−2h at infinity. Focusing on the z1-dependence in eq. (6.2.22) at fixed z2, this implies that g(z1, z2) falls as Image at infinity and so vanishes by holomorphicity. This determines the expectation value up to normalization. Comparing with the path integral result (6.2.19), there is agreement, though the normalization Image 1 ImageS2 is seen to diverge as Image(0). This is just the zero-mode divergence from the infinite volume of spacetime.

To obtain the expectation value of the product of vertex operators

Image

by this method is less direct, because the exponentials are not holomorphic. In fact they can be factored into holomorphic and antiholomorphic parts, but this is subtle and is best introduced in operator language as we will do in chapter 8. We use the holomorphicity of the translation current. Consider the expectation value with one current ImageX Image(z) added. The OPE of the current with the vertex operators determines the singularities in z,

Image

Now look at z → ∞. The condition that Imageu X Image be holomorphic at u = 0 again requires that the expectation value vanish as z−2 when z → ∞. The holomorphic term in eq. (6.2.25) must then vanish, and from the vanishing of the order z−1 term we recover momentum conservation,

Image

Let us also say this in a slightly different way. Consider the contour integral of the spacetime translation current

Image

where the contour C encircles all the exponential operators. There are two ways to evaluate this. The first is to contract C until it is a small circle around each vertex operator, which picks out the (zzi)−1 term from each OPE and gives Image. The second is to expand it until it is a small circle in the u-patch: by holomorphicity at u = 0 it must vanish. This sort of ‘contour-pulling’ argument is commonly used in CFT.

We have used the OPE to determine the singularities and then used holomorphicity to get the full z-dependence. Now we look at the second term of the OPE as zz1. Expanding the result (6.2.25) gives

Image

Contracting this with Image, the term of order (zz1)0 must agree with the OPE

Image

This implies

Image

Integrating, and using the conjugate equation and momentum conservation, determines the path integral up to normalization,

Image

in agreement with the first method. Note that to compare we must push the curvature to infinity (Image(Imagei) = 0) so that [  ]r = : :.

It is worth noting that the intermediate steps in the path integral method depend in a detailed way on the particular choice of Riemannian metric. The metric is needed in order to preserve coordinate invariance in these steps. A different, Weyl-equivalent, metric gives a different Laplacian and different eigenfunctions, though at the very end this dependence must drop out in string theory. The second method uses only the basic data of a Riemann surface, its holomorphic structure.

The disk

The generalization to the disk is straightforward. We will represent the disk by taking the above representation of the sphere and restricting z to the upper half of the complex plane. The Neumann boundary term is accounted for by an image charge,

Image

up to terms that drop out due to momentum conservation. Then

Image

For expectation values with ImageaX Images one again sums over contractions, now using the Green’s function (6.2.32). Note that Image (or Image) has a nonzero contraction.

For two points on the boundary, the two terms in the Green’s function (6.2.32) are equal, and the Green’s function diverges at zero separation even after normal ordering subtracts the first term. For this reason, boundary operators must be defined with boundary normal ordering, where the subtraction is doubled:

Image

with y denoting a coordinate on the real axis. The combinatorics are the same as for other forms of normal ordering. Boundary normal-ordered expectation values of boundary operators have the same good properties (nonsingularity) as conformal normal-ordered operators in the interior.

An expectation value with exponentials both in the interior and on the boundary, each having the appropriate normal ordering, is given by taking the appropriate limit of the interior result (6.2.33) and dropping the Image factor for the boundary operators. Explicitly, for exponentials all on the boundary,

Image

More generally,

Image

where now

Image

and the qs are contracted using −2Image′ (yy)−2ImageImageImage.

The projective plane

The method of images gives the Green’s function as

Image

Now

Image

and so on for more general expectation values. There is no boundary because the involution has no fixed points — there is no way for a point z to approach its image Image.

6.3    The bc CFT

The sphere

The path integral for the ghosts has already been set up in section 5.3. According to the Riemann–Roch theorem, the simplest nonvanishing expectation value will be

Image

Up to normalization (a functional determinant), the result (5.3.18) was just the zero-mode determinant,

Image

The six CKVs were found in section 6.1. In a complex basis they are

Image

In this basis the determinant splits into two 3 × 3 blocks, and the expectation value becomes

Image

The constant Image includes the functional determinant and also a finite-dimensional Jacobian (independent of the positions) that arises because the basis (6.3.3) is not orthonormal.

This is the only bc path integral that we will actually need for the tree-level amplitudes, but for completeness we give

Image

obtained by contracting the bs with cs. The antiholomorphic part ‘anti’ has the same form. We are being a little careless with the overall sign; again, for the Faddeev–Popov determinant we will in any case take an absolute value.

To give an alternative derivation using holomorphicity, we again consider first the conservation law, derived by inserting into the amplitude (6.3.5) the ghost number contour integral ImageC dz j(z)/2Imagei, where C encircles all the vertex operators and j = − :bc : is again the ghost number current. From the OPE with b and c, this just counts the number of c minus the number of b fields, giving ncnb times the original amplitude. Now pull the contour into the u-patch using the conformal transformation (2.5.17),

Image

The shift +3 comes about because j is not a tensor, having a z−3 term in its OPE with T . In the last step we use holomorphicity in the u-patch. The nonzero amplitudes therefore have ncnb = 3 and similarly nImagenImage = 3, in agreement with the Riemann–Roch theorem.

From the OPE, the ghost expectation value (6.3.1) is holomorphic in each variable, and it must have a zero when two identical anticommuting fields come together. Thus it must be of the form

Image

with F holomorphic and Image antiholomorphic functions of the positions. As z1 → ∞ this goes as Image. However, c is a tensor of weight −1, so the amplitude can be no larger than Image at infinity. Thus F(zi) must be independent of z1, and so also of z2 and z3; arguing similarly for Image we obtain again the result (6.3.4). The same argument gives for the general case (6.3.5) the result

Image

which has the correct poles, zeros, and behavior at infinity. The permutations (6.3.5) evidently sum up to give this single term.

We have considered the Image =2 theory that is relevant to the ghosts of the bosonic string, but either method generalizes readily to any Image.

The disk

The simplest way to obtain the bc amplitudes on the disk is with the doubling trick. As in eq. (2.7.30), we can represent both the holomorphic and antiholomorphic fields in the upper half-plane by holomorphic fields in the whole plane, using

Image

The expectation value of the holomorphic fields follows as on the sphere,

Image

for all z. Then for example

Image

More general correlators are obtained in the same way.

The projective plane

The doubling trick again can be used. The involution Image implies that

Image

Again

Image

and so

Image

6.4    The Veneziano amplitude

Open string amplitudes are slightly simpler than closed string amplitudes, so we begin with these.

We represent the disk as the upper half-plane so the boundary coordinate y is real. There are no moduli. After fixing the metric, the CKG PSL(2, R) can be used to fix the three vertex operators to arbitrary positions y1, y2, y3 on the boundary, except that this group does not change the cyclic ordering of the vertex operators so we must sum over the two orderings. For three open string tachyons on the disk, the general expression (5.3.9) for the string S-matrix thus reduces to

Image

each fixed coordinate integration being replaced by the corresponding c-ghost. Each vertex operator includes a factor of go, the open string coupling. The factor ImageImage is from the Euler number term in the action. Of course go and ImageImage are related, Image, but we will determine the constant of proportionality as we go along.

The expectation values in (6.4.1) were found in the previous sections (again, we take the absolute value for the ghosts), giving

Image

where Image. Momentum conservation and the mass-shell condition Image imply that

Image

and the same for the other ki · kj, so this reduces to

Image

This is independent of the gauge choice yi, which is of course a general property of the Faddeev–Popov procedure. The Weyl invariance is crucial here — if the vertex operators were taken off the mass shell, the amplitude would depend on the choice of yi.

We could have used independence of the yi to determine the Faddeev–Popov determinant without calculation. Using the mass-shell condition and momentum conservation, the XImage expectation value is proportional to |y12 y13 y23|−1, and so the measure must be reciprocal to this. This same measure then applies for n > 3 vertex operators, because in all cases three positions are fixed.

The four-tachyon amplitude is obtained in the same way,

Image

This is again independent of y1,2,3 after a change of variables (a Möbius transformation) on y4. It is convenient to take y1 = 0, y2 = 1, and y3 → ∞. The amplitude is conventionally written in terms of the Mandelstam variables

Image

These are not independent: momentum conservation and the mass-shell condition imply that

Image

Using 2Imageki · kj = −2 + Image′ (ki + kj)2, the amplitude becomes

Image

The integral splits into three ranges, −∞ < y4 < 0, 0 < y4 < 1, and 1 < y4 < ∞. For these three ranges the vertex operators are ordered as in figures 6.2(a), (b), and (c) respectively. Möbius invariance can be used to take each of these ranges into any other, so they give contributions that are equal up to interchange of vertex operators. The (ts) term gives figures 6.2(d), (e), and (f). In all,

Image

Fig. 6.2.   The six cyclically inequivalent orderings of four open string vertex operators on the disk. The coordinate y increases in the direction of the arrow, except that at point 3 it jumps from +∞ to −∞

Image

where

Image

The three terms come from figures 6.2(c), (f), 6.2(b), (d), and 6.2(a), (e) respectively.

The integral I(s, t) converges if Images < − 1 and Imaget < −1. As Images → −1, the integral diverges at y = 0. To study the divergence, take a neighborhood of y = 0 and approximate the integrand:

Image

In (6.4.11), we have evaluated the integral in the convergent region. We see that the divergence is a pole at s = −1/Image′ , the mass-squared of the open string tachyon. The variable s is just the square of the center-of-mass energy for scattering 1 + 2 → 3 + 4, so this pole is a resonance due to an intermediate tachyon state. Again, it is an artifact of the bosonic string that this lightest string state is tachyonic, and not relevant to the discussion. The pole is due to the process shown in figure 6.3(a), in which tachyons 1 and 2 join to become a single tachyon, which then splits into tachyons 3 and 4.

Image

Fig. 6.3.   Processes giving poles in the (a) s-, (b) t-, and (c) u-channels.

Because the singularity at Images = −1 is just a pole, I(s, t) can be analytically continued past this point into the region Images > −1. The amplitude is defined via this analytic continuation. The divergence of the amplitude at the pole is an essential physical feature of the amplitude, a resonance corresponding to propagation of the intermediate string state over long spacetime distances. The divergence of the integral past the pole is not; it is just an artifact of this particular integral representation of the amplitude. The continuation poses no problem. In fact, we will see that every string divergence is of this same basic form, so this one kind of analytic continuation removes all divergences — except of course for the poles themselves. The pole is on the real axis, so we need to define it more precisely. The correct Image prescription for a Minkowski process is

Image

where P denotes the principal value. Unitarity (which we will develop more systematically in chapter 9) requires this pole to be present and determines its coefficient in terms of the amplitude for two tachyons to scatter into one:

Image

Gathering together the factors in the four-tachyon amplitude, including an equal contribution to the pole from I(u, s), and using the three-tachyon result (6.4.4), the condition (6.4.13) gives

Image

The three-tachyon amplitude is then

Image

The various functional determinants have dropped out. Using unitarity, all normalizations can be expressed in terms of the constant go appearing in the vertex operators. The determinants can in fact be computed by careful regularization and renormalization, and the relative normalizations of different topologies agree with those from unitarity.

Continuing past the pole, we encounter further singularities. Taylor expanding the integrand at y = 0 gives

Image

The second term gives a pole at Images = 0,

Image

From the further terms in the Taylor expansion, the amplitude has poles at

Image

These are precisely the positions of the open string states. The integral I(s, t) also has poles in the variable t at the same positions (6.4.18), coming from the endpoint y = 1. These are due to the process of figure 6.3(b). The other two terms in the amplitude (6.4.9) give further contributions to the s- and t-channel poles, and also give poles in the u-channel, figure 6.3(c). Because the residue at s = 0 in (6.4.17) is odd in ut, this pole actually cancels that from I(s, u), as do all poles at even multiples of 1/Image′. This will not be true for the more general open string theories to be introduced in the next section.

Define the Euler beta function

Image

so that

Image

This can be expressed in terms of gamma functions. Defining y = Image / w for fixed w gives

Image

Multiplying both sides by Imagew, integrating Image, and regrouping gives

Image

The four-tachyon amplitude is then

Image

where

Image

This is the Veneziano amplitude, originally written to model certain features of strong interaction phenomenology.

The high energy behavior of the Veneziano amplitude is important. There are two regions of interest, the Regge limit,

Image

and the hard scattering limit,

Image

If we consider the scattering process 1 + 2 → 3 + 4 (so that Image and Image are positive and Image and Image negative), then in the 1-2 center-of-mass frame,

Image

where E is the center-of-mass energy and Image is the angle between particle 1 and particle 3. The Regge limit is high energy and small angle, while the hard scattering limit is high energy and fixed angle. Using Stirling’s approximation, Γ(images + 1) Image imagesimages Imageimages(2Image images)1/2, the behavior in the Regge region is

Image

where again Imageo(t) = Imaget + 1. That is, the amplitude varies as a power of s, the power being t-dependent. This is Regge behavior. At the poles of the gamma function, the amplitude is an integer power of s, corresponding to exchange of a string of integer spin Imageo(t).

In the hard scattering limit,

Image

where

Image

is positive. The result (6.4.29) is notable. High energy, fixed angle scattering probes the internal structure of the objects being scattered. Rutherford discovered the atomic nucleus with hard alpha–atom scattering. Hard electron–nucleon scattering at SLAC revealed the quark constituents of the nucleon. In quantum field theory, hard scattering amplitudes fall as a power of s. Even a composite object like the nucleon, if its constituents are pointlike, has power law amplitudes. The exponential falloff (6.4.29) is very much softer. The result (6.4.29) suggests a smooth object of size Image1/2, as one would expect.

We started with the three-particle amplitude, skipping over the zero-, one-, and two-particle amplitudes. We will discuss these amplitudes, and their interpretation, in section 6.6.

6.5    Chan–Paton factors and gauge interactions

In this section we will consider the interactions of the massless vector state of the open string. To make the discussion a bit more interesting, we first introduce a generalization of the open string theory.

At the end of chapter 3 we introduced a very large class of bosonic string theories, but in this first look at the interactions we are focusing on the simplest case of 26 flat dimensions. One can think of this in terms of symmetry: this theory has the maximal 26-dimensional Poincaré invariance. In the closed bosonic string this is the unique theory with this symmetry. An outline of the proof is as follows. The world-sheet Noether currents for spacetime translations have components of weights (1, 0) and (0, 1). By an argument given in section 2.9, these currents are then holomorphic in z or Image. We have seen in the calculations in this chapter that this is enough to determine all the expectation values.

Image

Fig. 6.4.   Open string with Chan–Paton degrees of freedom.

In open string theory, however, there is a generalization. The open string has boundaries, endpoints. In quantum systems with distinguished points it is natural to have degrees of freedom residing at those points in addition to the fields propagating in the bulk. At each end of the open string let us add a new degree of freedom, known as a Chan–Paton degree of freedom, which can be in one of n states. A basis of string states is then

Image

where i and j denote the states of the left- and right-hand endpoints, running from 1 to n. The energy-momentum tensor is defined to be the same as before, with no dependence on the new degrees of freedom. Conformal invariance is therefore automatic. Poincaré invariance is automatic as well, as the Chan–Paton degrees of freedom are invariant. Although these new degrees of freedom have trivial world-sheet dynamics, they will have a profound effect on the spacetime physics.

In string theories of the strong interaction, the motivation for this was to introduce SU(3) flavor quantum numbers: the endpoints are like quarks and antiquarks, connected by a color-electric flux tube. Now we are motivating it in the general framework of considering all possibilities with given symmetries. We will give a new interpretation to the Chan–Paton degrees of freedom in chapter 8, and a possible further refinement in chapter 14.

There are now n2 scalar tachyons, n2 massless vector bosons, and so forth. The n2 Hermitian matrices Image, normalized to

Image

are a complete set of states for the two endpoints. These are the representation matrices of U(n), so one might guess that the massless vectors are associated with a U(n) gauge symmetry; we will soon see that this is the case.

Define the basis

Image

Now consider the four-tachyon amplitude shown in figure 6.2(a), in which the vertex operators are arranged in the cyclic order 1234. Because the Chan–Paton degrees of freedom do not appear in the Hamiltonian, their state does not evolve between the vertex operators: the right-hand endpoint of tachyon 1 must be in the same state as the left-hand endpoint of tachyon 2, and so forth. Thus, the amplitude 6.2(a) will now contain an additional factor of

Image

from the overlap of the Chan–Paton wavefunctions for each tachyon. This rule generalizes to an arbitrary amplitude: each vertex operator now contains a Chan–Paton factor Image from the wavefunction of the endpoint degrees of freedom, and the amplitude for each world-sheet is multiplied by a trace of the Chan–Paton factors around each boundary.

The three-tachyon amplitude becomes

Image

the two cyclic orderings now having different Chan–Paton traces. The four-tachyon amplitude is

Image

Considering again the unitarity relation (6.4.13), the pole at s = −1/Image′ acquires a factor of

Image

on the left and a factor of

Image

on the right, the sum being over the Chan–Paton wavefunction of the intermediate state. The completeness of the Image and the normalization (6.5.2) imply that

Image

for any matrices A and B, and so the amplitudes are still unitary.

Gauge interactions

The amplitude for a gauge boson and two tachyons is

Image

We have used the gauge boson vertex operator (3.6.26), but for now are allowing an independent normalization constant Image. Using the results of section 6.2, the X path integral is

Image

Using momentum conservation, the mass-shell conditions, and the physical state condition k1· Image1 = 0, the amplitude becomes

Image

where kijkikj. This is again independent of the vertex operator positions.

The s = 0 pole in the four-tachyon amplitude no longer vanishes. The terms that canceled now have the Chan–Paton factors in different orders, so the pole is proportional to

Image

Relating the coefficient of this pole to the amplitude (6.5.12) by unitarity, one obtains

Image

This is the same relative normalization as from the state–operator mapping: there is only one independent coupling constant.

For the three-gauge-boson coupling, a similar calculation gives

Image

Up to first order in the momenta, the amplitudes we have found are reproduced by the spacetime action

Image

where the tachyon field Image and the Yang–Mills vector potential AImage are written as n × n matrices, e. g. Image. Also, DImageImage = ImageImageImagei[AImage, Image] and FImageImage = ImageImage AImageImageImage AImagei[AImage, AImage].

This is the action for a U(n) gauge field coupled to a scalar in the adjoint representation. Adding in the Chan–Paton factors has produced just the gauge-invariant expressions needed. The gauge invariance is automatic because the decoupling of unphysical states is guaranteed in string perturbation theory, as we will develop further.

At momenta k small compared to the string scale, the only open string states are the massless gauge bosons. As discussed in section 3.7, it is in this limit that the physics should reduce to an effective field theory of the massless states. We have therefore been somewhat illogical in including the tachyon in the action (6.5.16); we did so for illustration, but now let us focus on the gauge bosons. The four-gauge-boson amplitude has a form analogous to the Veneziano amplitude but with additional structure from the polarization tensors. Expanding it in powers of Imagek2, the first term, which survives in the zero-slope limit Image′ → 0, is the sum of pole terms in s, t, and u plus a constant. Consistency guarantees that it is precisely the four-gauge-boson amplitude obtained in field theory from the Yang–Mills Lagrangian FImageImage FImageImage. Note, however, the term of order Imagek3 in the three-gauge-boson amplitude (6.5.15). This implies a higher derivative term

Image

in the Lagrangian. Similarly, expanding the four-point amplitude reveals an infinite sum of higher order interactions (beyond (6.5.17), these do not contribute to the three-gauge-boson amplitude for kinematic reasons). String loop amplitudes also reduce, in the low energy region, to the loops obtained from the effective Lagrangian. By the usual logic of effective actions, the higher derivative terms are less important at low energy. The scale where they become important, Imagek2 Image 1, is just where new physics (massive string states) appears and the effective action is no longer applicable.

If we have a cutoff, why do we need renormalization theory? Renormalization theory still has content and in fact this is its real interpretation: it means that low energy physics is independent of the details of the high energy theory, except for the parameters in the effective Lagrangian. This is a mixed blessing: it means that we can use ordinary quantum field theory to make predictions at accelerator energies without knowing the form of the Planck scale theory, but it also means that we cannot probe the Planck scale theory with physics at particle accelerators.

The string spectrum and amplitudes have an obvious global U(n) symmetry,

Image

which leaves the Chan–Paton traces and the norms of states invariant. From the detailed form of the amplitudes, we have learned that this is actually a local symmetry in spacetime. We will see that this promotion of a global world-sheet symmetry to a local spacetime symmetry is a rather general phenomenon in string theory.

All open string states transform as the n × n adjoint representation under the U(n) symmetry. Incidentally, U(n) is not a simple Lie algebra: U(n) = SU(n) × U(1). The U(1) gauge bosons, Imageij = Imageij / n1/2, decouple from the amplitudes (6.5.12) and (6.5.15). The adjoint representation of U(1) is trivial, so all string states are neutral under the U(1) symmetry.

The unoriented string

It is interesting to generalize to the unoriented string. Consider first the theory without Chan–Paton factors. In addition to Möbius invariance, the X Image CFT on the sphere or disk is invariant under the orientation-reversing symmetry Image1ImageImage1 in the open string or Image1 → 2ImageImage1 in the closed string. This world-sheet parity symmetry is generated by an operator Ω. From the mode expansions it follows that

Image

in the open string and

Image

in the closed string. The symmetry extends to the ghosts as well, but to avoid distraction we will not discuss them explicitly, since they only contribute a fixed factor to the tree-level amplitudes.

The tachyon vertex operators are even under world-sheet parity in either the closed or open string (this is obvious for the integrated vertex operators, without ghosts; the fixed operators must then transform in the same way), determining the sign of the operator. All states can then be classified by their parity eigenvalue Image = ± 1. The relation (6.5.19) in the open string implies that

Image

World-sheet parity is multiplicatively conserved. For example, the three-tachyon amplitude is nonzero, consistent with (+1)3 = 1. On the other hand, the massless vector has Image = −1 and so we would expect the vector–tachyon–tachyon amplitude (6.5.10) and three-vector amplitude (6.5.15) to vanish in the absence of Chan–Paton degrees of freedom, as indeed they do (the Imagea are replaced by 1 and the commutators vanish). The different cyclic orderings, related to one another by world-sheet parity, cancel.

Given a consistent oriented string theory, we can make a new unoriented string theory by restricting the spectrum to the states of Image = +1. States with odd Imagem2 remain, while states with even Imagem2, including the photon, are absent. The conservation of Image guarantees that if all external states have Image = +1, then the intermediate states in tree-level amplitudes will also have Image = +1. Unitarity of the unoriented theory thus follows from that of the oriented theory, at least at tree level (and in fact to all orders, as we will outline in chapter 9).

The main point of interest in the unoriented theory is the treatment of the Chan–Paton factors. Since we have identified these with the respective endpoints of the open string, world-sheet parity must reverse them,

Image

Again, this is a symmetry of all amplitudes in the oriented theory. To form the unoriented theory, we again restrict the spectrum to world-sheet parity eigenvalue Image = +1. Take a basis for Image in which each matrix is either symmetric, sa = +1, or antisymmetric, sa = −1. Then

Image

The world-sheet parity eigenvalue is Image = ImageNsa, and the unoriented spectrum is

Image

For the massless gauge bosons the Chan–Paton factors are the n × n antisymmetric matrices and so the gauge group is SO(n). The states at even mass levels transform as the adjoint representation of the orthogonal group SO(n), and the states at odd mass levels transform as the traceless symmetric tensor plus singlet representations.

The oriented theory has a larger set of orientation-reversing symmetries, obtained as a combination of Ω and a U(n) rotation,

Image

We can form more general unoriented theories by restricting the spectrum to ImageImage = +1, which is again consistent with the interactions. Acting twice with ΩImage gives

Image

We will insist that Image for reasons to be explained below. This then implies that

Image

That is, Image is symmetric or antisymmetric.

A general change of Chan–Paton basis,

Image

transforms Image to

Image

In the symmetric case, it is always possible to find a basis such that Image = 1, giving the theory already considered above. In the antisymmetric case there is a basis in which

Image

Here I is the k × k identity matrix and n = 2k must be even because Image is an invertible antisymmetric matrix. We take a basis for the Chan–Paton wavefunctions such that M(Imagea)T M = sa Imagea with sa = ±1. Then the world-sheet parity eigenvalue is ImageImage = ImageN sa, and the unoriented spectrum is

Image

At the even mass levels, including the gauge bosons, this defines the adjoint representation of the symplectic group Sp(k).

The argument that we must have Image = 1 to construct the unoriented theory is as follows. Since Ω2 = 1, it must be that Image acts only on the Chan–Paton states, not the oscillators. In fact, from eq. (6.5.26), it acts on the Chan–Paton wavefunction as

Image

where the last equality must hold in the unoriented theory, since all states in this theory are invariant under ΩImage and so also under Image. Now we assert that the allowed Chan–Paton wavefunctions must form a complete set. The point is that two open strings, by the splitting–joining interaction of figure 3.4(c), can exchange endpoints. In this way one can get to a complete set, that is, to any Chan–Paton state |i jImage (this argument is slightly heuristic, but true). By Schur’s lemma, if eq. (6.5.32) holds for a complete set, then Image−1ImageT = 1 and so Image.

We might try to obtain other gauge groups by taking different sets of Imagea. In fact, the oriented U(n) and unoriented SO(n) and Sp(k) theories constructed above are the only possibilities. Generalization of the completeness argument in eqs. (6.5.7)–(6.5.9) shows these to be the most general solutions of the unitarity conditions. In particular, exceptional Lie algebras, which are of interest in grand unification and which will play a major role in volume two, cannot be obtained with Chan–Paton factors (in perturbation theory). In closed string theory there is another mechanism that gives rise to gauge bosons, and it allows other groups.

6.6    Closed string tree amplitudes

The discussion of closed string amplitudes is parallel to the above. The amplitude for three closed string tachyons is

Image

In this case the CKG PSL(2, C) (the Möbius group) can be used to fix the three vertex operators to arbitrary positions z1,2,3. Taking the expectation values from section 6.2, the result is again independent of the vertex operator positions,

Image

where Image.

For four closed string tachyons,

Image

where the integral runs over the complex plane C. Evaluating the expectation value and setting z1 = 0, z2 = 1, z3 = ∞, this becomes

Image

where

Image

Here s + t + u = −16/Image′, but we indicate the dependence of J on all three variables to emphasize its symmetry among them. This amplitude converges when s, t, u < −4/Image′. It has poles in the variable u from z4 → 0, in the variable t from z4 → 1, and in the variable s from z4 → ∞. The poles are at the values

Image

which are the masses-squared of the closed string states. The pole at Images = −4 is

Image

Unitarity gives

Image

and so

Image

Like the Veneziano amplitude, the amplitude for four closed string tachyons can be expressed in terms of gamma functions (exercise 6.10):

Image

where Imagec(images) = 1 + Imageimages/4 and

Image

This is the Virasoro–Shapiro amplitude. There is just a single term, with poles in the s-, t-, and u-channels coming from the gamma functions in the numerator. Like the Veneziano amplitude, the Virasoro–Shapiro amplitude has Regge behavior in the Regge limit,

Image

and exponential behavior in the hard scattering limit,

Image

On the sphere, the amplitude for a massless closed string and two closed string tachyons is

Image

where Image. Expanding the Virasoro–Shapiro amplitude (6.6.10) on the s = 0 pole and using unitarity determines

Image

again in agreement with the state–operator mapping with overall constant gc. The amplitude (6.6.14) would be obtained in field theory from the spacetime action S + ST , where S is the action (3.7.20) for the massless fields, and where

Image

is the action for the closed string tachyon T . For example, the amplitude for a graviton of polarization ImageImageImage is obtained from this action by expanding

Image

Note that this is the Einstein metric, whose action (3.7.25) is independent of the dilaton. The normalization of the fluctuation is determined by that of the graviton kinetic term in the spacetime action. Specifically, if one takes ImageImageImageImageImageImage = −2ImageImageImageImage Image(images) with ImageImageImage ImageImageImage = 1, the effective action for Image has the canonical normalization Image for a real scalar. The field theory amplitude matches the string result (6.6.14) and relates the normalization of the vertex operators to the gravitational coupling,

Image

The amplitude for three massless closed strings is

Image

where

Image

The order k2 terms in this amplitude correspond to the spacetime action (3.7.25), while the k4 and k6 terms come from a variety of higher derivative interactions, including terms quadratic and cubic in the space-time curvature. These higher corrections to the action can also be determined by calculating higher loop corrections to the world-sheet beta functions (3.7.14).

The tensor structure of the closed string amplitude (6.6.19) is just two copies of that in the open string amplitude (6.5.15), if one sets Image′ = 2 in the closed string and Image′ = Image in the open. The same holds for the amplitude (6.6.14). This is a consequence of the factorization of free-field expectation values on the sphere into holomorphic and antiholomorphic parts. A similar factorization holds for four or more closed strings before integration over the vertex operator positions. Further, by careful treatment of the contour of integration it is possible to find relations between the integrated amplitudes. For the four-tachyon amplitudes the integrals above are related

Image

after use of the gamma function identity Γ(images)Γ(1−images) sin(Imageimages) = Image; we now indicate the explicit dependence of the integrals on Image′. For the general integral appearing in four-point closed string amplitudes there is a relation

Image

This implies a corresponding relation between four-point open and closed string amplitudes

Image

where the open string amplitudes include just one of the six cyclic permutations, with poles in the indicated channels.

Consistency

In chapter 9 we will discuss the convergence and gauge invariance of tree-level amplitudes in a general way, but as an introduction we will now use the OPE to see how these work for the lowest levels. Consider the operator product

Image

This appears in the amplitude with z14 integrated. The integral converges as z14 → 0 when

Image

and has a pole at that point. The coefficient of the pole is just the tachyon vertex operator. Thus, if a pair of tachyons in any amplitude has total momentum (k1 + k4)2 = 4/Image′, there will be a pole proportional to the amplitude with one fewer tachyon as required by unitarity. A pole in momentum space corresponds to long distance in spacetime, so this is a process in which two tachyons scatter into one, which then propagates and interacts with the remaining particles. Carrying the OPE further, the O(z14) and O(Image14) terms do not produce poles because the angular integration gives zero residue, the O(z14Image14) term gives a massless pole, and so on.

Now let us look a little more closely at the way the local spacetime symmetries are maintained in the string amplitudes. The various amplitudes we have calculated all vanish if any of the polarizations are of the form ImageImage = kImage, or ImageImageImage = ImageImageKImage + KImageImageImage with k · Image = K · Image = 0. The corresponding spacetime actions are thus invariant under the Yang–Mills, coordinate, and antisymmetric tensor symmetries. As discussed in section 3.6, the vertex operator for a longitudinal polarization is the sum of a total derivative and a term that vanishes by the equations of motion. Upon integration, the total derivative vanishes but the equation of motion term might have a source at one of the other vertex operators in the path integral. The operator product (6.6.24) vanishes rapidly when k1 · k4 is large. Using this property, there will be for any pair of vertex operators a kinematic region in which all possible contact terms are suppressed. The amplitude for any null polarization then vanishes identically in this region, and since all amplitudes are analytic except for poles (and branch points at higher order) the amplitudes for null polarizations must vanish everywhere. We see that the singularities required by unitarity, as well as any possible divergences or violations of spacetime gauge invariance, arise from the limits z → 0, 1, ∞, where two vertex operators come together. For the sphere with four marked points (vertex operators) these are the boundaries of moduli space. The analytic continuation argument used here is known for historic reasons as the canceled propagator argument.

Closed strings on D2 and RP2

The lowest order closed–open interactions come from the disk with both closed and open vertex operators. The low energy effective action for these can be deduced from general considerations. With a trivial closed string background we found the usual gauge kinetic term,

Image

Obviously the metric must couple to this in a covariant way. In addition, the coupling of the dilaton can be deduced. Recall that Image, with Φ0 the expectation value of the dilaton. So we should replace this (inside the integral) with Φ = Φ0 + Image. The action

Image

thus incorporates all interactions not involving derivatives of the closed string fields; indices are now raised and lowered with GImageImage. This action reflects the general principle that the effective action from Euler number Image is weighted by Image.

The disk and projective plane also make a contribution to purely closed string interactions. The amplitudes for n closed strings are of order Image, one power of gc higher than the sphere. Closed string loop amplitudes, to be considered in the next chapter, are of order Image times the sphere, because emitting and reabsorbing a closed string adds two factors of gc. Thus the disk and projective plane are ‘half-loop order.’

Of particular interest are the amplitudes on the disk and the projective plane with a single closed string vertex operator. Fixing the position of the vertex operator removes only two of the three CKVs, the residual gauge symmetry consisting of rotations about the vertex operator position. Thus we have to divide the amplitude by the volume of this residual CKG. We have not shown how to do this explicitly, but will work it out for the torus in the next chapter. For the disk with one closed string this is a finite factor and the result is nonzero. The amplitude is a numerical factor times Image which in turn is a pure number, times powers of Image′ as required by dimensional analysis. We will not work out these numerical factors here, but will obtain them in an indirect way in chapter 8.

Thus there is an amplitude for a single closed string to appear from the vacuum, either through the disk or the projective plane, necessarily with zero momentum. Such an amplitude is known as a tadpole. In other words, the background closed string fields are corrected from their original values at order gc. Again we can write an effective action, which is simply

Image

the Φ dependence deduced as above. This is a potential for the dilaton. We will consider it further in the next chapter.

The amplitude for a single closed string on the sphere, on the other hand, is zero. The residual CKG is a noncompact subgroup of PSL(2, C) and so one has to divide by an infinite volume. A nonzero result would have been a logical inconsistency, a zeroth order correction to the background fields. Similarly the amplitude for two closed strings on the sphere (a zeroth order correction to the mass) vanishes, as do the corresponding disk amplitudes, one or two open strings. The amplitudes with no vertex operators at all are also meaningful — they just calculate the term of order Image in the Taylor expansion of the action (6.6.28). The disk amplitude with no vertex operators is thus nonvanishing; this requires a somewhat formal treatment of the conformal Killing volume.

6.7    General results

In this section we obtain some general results concerning CFT on the sphere and disk.

Möbius invariance

We have seen that the sphere has a group of globally defined conformal transformations, the Möbius group PSL(2, C),

Image

for complex Image, Image, Image, Image with ImageImageImageImage = 1. This is the most general conformal transformation that is one-to-one on all of S2, the complex z-plane plus the point at infinity. Expectation values must be invariant under any Möbius transformation:

Image

We will consider the consequences of this symmetry for expectation values with one, two, three, or four local operators.

For a single operator of weight (hi, Imagei), the rescaling plus rotation z = Imagez gives

Image

The one-point function therefore vanishes unless hi = Imagei = 0. This is another way to see that the one-point string amplitude vanishes on the sphere, because the matter factor is the expectation value of a (1, 1) operator.

For n = 2, we can use a translation plus z = Imagez to bring any pair of operators to the points 0 and 1, giving

Image

so the position dependence is completely determined. Single-valuedness implies that Ji +JjImage, where Ji = hiImagei. There is a further constraint on the two-point function from the conformal transformation z = z + Image(zz1)(zz2) + O(Image2), which leaves z1 and z2 fixed. For general operators this is complicated, but for tensor fields Image and Image it simply implies that

Image

Any three points z1,2,3 can be brought to given positions by a Möbius transformation. For n ≥ 3, Möbius invariance therefore reduces the expectation value from a function of n complex variables to a function of n − 3 complex variables. Again the result takes a simple form only for tensor fields. For example, for three tensor fields one finds

Image

where Cp1p2p3 is independent of position and h = h1 + h2 + h3. For four primary fields,

Image

where Image, and zc = z12z34/z13z24 is the Möbius invariant cross-ratio. The function Cp1p2p3p4(zc, Imagec) is not determined by conformal invariance, so we are reduced from a function of four variables to an unknown function of one variable.

On the disk represented as the upper half-plane, only the Möbius transformations with Image,Image,Image,Image real remain, forming the group PSL(2, R). The extension of the above is left as an exercise. One learns much more by considering the full conformal algebra. We will see in chapter 15 that it determines all expectation values in terms of those of the tensor fields.

Path integrals and matrix elements

The path integrals we have considered can be related to operator expressions. Consider the path integral on the sphere with two operators, one at the origin and one at infinity:

Image

The prime indicates the u-frame, which we have to take for the operator at infinity; by a slight abuse of notation we still give the position in terms of z. Using the state–operator mapping we can replace the disk |z| < 1 containing Image at z = 0 by the state Image on the circle |z| = 1. We can also replace the disk |z| > 1 (|u| < 1) containing Image at u = 0 by the state Image on the circle |z| = 1. All that is left is the integral over the fields Imageb on the circle, so the expectation value (6.7.8) becomes

Image

here Image, arising from the mapping zu = 1.

This convolution of wavefunctions resembles an inner product, so we define

Image

This is essentially the inner product introduced by Zamolodchikov. For tensor operators in unitary theories, a Möbius transformation shows that this is the same as the coefficient of 1 in the OPE,

Image

We have abbreviated Image to |iImage. The Image product is not the same as the quantum mechanical inner product Image | Image introduced in chapter 4. The latter is Hermitean, whereas the former includes no complex conjugation and so is bilinear, up to a sign if i and j are anticommuting. That is,

Image

since all we have done is to interchange the two operators and rename zu. There is a simple relation between the two inner products, which we will develop later.

We will sometimes write Imageij for Image, and Imageij for the inverse matrix, where i, j run over a complete set. The matrices Imageij and Imageij will be used to raise and lower indices, Imagei = Imageij Imagej, Imagei = ImageijImagej.

Operators in the path integral translate in the usual way into operators in Hilbert space. For example,

Image

where we reintroduce the hat to emphasize that we are in a Hilbert space formalism. Using the OPE, the left-hand side becomes

Image

Thus the three-point expectation values on the sphere, the OPE coefficients with all indices lowered, and the matrix elements of general local operators are all the same thing. By a Möbius transformation (rescaling of z) we have also

Image

The four-point function translates into an operator expression

Image

where T denotes radial ordering. Let |z1| > |z2| and insert a complete set of states,

Image

The four-point amplitude (6.7.16) becomes

Image

Thus, the operator product coefficients determine not only the three-point expectation values on the sphere, but also the four-point and, by the same construction, arbitrary n-point amplitudes. For |z1z2| > |z1|, which overlaps the region |z1| > |z2| where the expansion (6.7.18) is valid, we can translate Imagek to the origin and give a similar expansion in terms of Image. The equality of these two expansions is associativity of the OPE, figure 2.8.

Operator calculations

The Hilbert space expressions give us one more way to calculate expectations values. We take as an example the case of four exponential operators

Image

We have used the result (2.7.11) that : : ordered operators are the same as Image ordered operators for this CFT. We have abbreviated X Image (zi, Imagei) as Image and to avoid clutter are omitting the hats on operators. By definition

Image

where

Image

For |z1| > |z2| the matrix element (6.7.19) becomes

Image

To evaluate this use the Campbell–Baker–Hausdorff (CBH) formula

Image

The expectation value (6.7.22) becomes

Image

where we have used the two-point expectation value to normalize the last line. This is the familiar result (6.2.31), obtained by two other methods in section 6.2, after one includes in the latter a factor Image from the change of frame and takes z4 → ∞. All other free-field results can be obtained by this same oscillator method.

Relation between inner products

Nondegenerate bilinear and Hermitean inner products can always be related to one another by an appropriate antilinear operation on the bra. Let us consider an example. From the free-field expectation values, we have

Image

using the fact that |0;kImage maps to Imageik·X. Compare this with the inner product from the X Image CFT,

Image

These differ only by k → −k from conjugating Imageik·X, and normalization,

Image

For more general operators, there is a natural notion of conjugation in CFT. In Euclidean quantum mechanics, Hermitean conjugation inverts Euclidean time, eq. (A.1.37), so the natural operation of Euclidean conjugation is conjugation × time-reversal: an operator that is Hermitean in Minkowski space is also Hermitean under this combined operation. In CFT, we make the same definition, but also must include a time-reversal on the conformal frame,

Image

Here p and p are related by radial time-reversal, z = Image−1, and the unprimed operator is in the z-frame and the primed operator in the u- frame. To see how this works, consider a holomorphic operator of weight h, whose Laurent expansion is

Image

Its simple adjoint is

Image

Then the Euclidean adjoint is

Image

For an operator that is Hermitean in Minkowski time, Image, and so this operator is also Hermitean3 under Image. The Euclidean adjoint (6.7.28) conjugates all explicit factors of i, but leaves z and Image indices unchanged. This is its whole effect, other than an overall factor (−1)Na(Na − 1)/2 from reversing the order of anticommuting fields; here Na is the total number of anticommuting fields in the operator.

This is the natural conformally invariant operation of conjugation, so it must be that

Image

for some constant K. For a direct demonstration, the best we have come up with is

Image

The only step here that is not either a definition or obvious is the assumption of proportionality, Image1| = K Image1|. This must hold because |1Image is the unique SL(2, C)-invariant state.

For the X CFT we have seen that Image. For the ghost CFT, the Laurent expansion of the amplitude (6.3.4) gives Image, where |0Image = Image1c1|1Image. The Hermitean inner product was defined in eq. (4.3.18) as Image0|Image0c0|0Image = i, so Image.

Except for the is, which are absent in a unitary CFT, one can set K = 1 by adding an Euler number term to the action. In a Hermitean basis of operators, the two inner products are then identical, and the distinction between them is often ignored. Notice, however, that a vertex operator of definite nonzero momentum cannot be Hermitean.

Again, this can all be extended to the open string, with the disk in place of the sphere.

Exercises

6.1 Verify that the expectation value (6.2.31) is smooth in the u-patch.

6.2 For the linear dilaton CFT, Φ = VImageXImage, the XImage zero-mode path integral diverges. This reflects the fact that the coupling is diverging in some direction. Consider therefore imaginary Φ = ibImageXImage; this is unphysical but has technical applications (one could instead take complex momenta).
(a) Generalize the calculation that gave (
6.2.17) to this case. Show that in the end the only changes are in the Weyl dependence (reflecting a change in the dimension of the exponential) and in the spacetime momentum conservation.
(b) Generalize the calculation of the same quantity using holomorphicity. Show that the result is the same as in the regular XImage CFT but with an extra background charge operator exp(−2ib · X) taken to infinity.

6.3 For one b and four c fields, show that expressions (6.3.5) and (6.3.8) are equal. Ignore the antiholomorphic fields.

6.4 (a) Write the amplitude for n open string tachyons on the disk as a generalization of eq. (6.4.5).
(b) Show by a change of variables that it is independent of the positions of the fixed vertex operators.

6.5 (a) Show that the residue of the pole in I(s, t) at Images = J − 1 is a polynomial in ut of degree J, corresponding to intermediate particles of spin up to J.
(b) Consider the amplitude I(s, t) without assuming D = 26. In the center-of-mass frame, write the residue of the pole at Images = 1 in terms of

Image

where P0 projects onto spin 0 (the unit matrix) and P2 projects onto spin 2 (traceless symmetric tensors). Show that the coefficient of P 0 is positive for D < 26, zero at D = 26, and negative at D > 26. Compare with the expected string spectrum at this level, and with the discussion of this level in section 4.1.

6.6 (a) In the hard scattering limit, evaluate the integral in the Veneziano amplitude (6.4.5) using the saddle point approximation. Take the naive saddle point; the justification requires consideration of the analytic continuations needed to define the integral.
(b) Do the same for the Virasoro–Shapiro amplitude.

6.7 (a) Derive the amplitude (6.5.12).
(b) Verify the relation (6.5.14) between vertex operator normalizations. Show that this agrees with the state–operator mapping.

6.8 Derive the three-gauge-boson amplitude (6.5.15).

6.9 (a) Obtain the four-gauge-boson amplitude. To reduce the rather extensive algebra, consider only those terms in which the polarizations appear as Image1 · Image2 Image3 · Image4.
(b) Compare the behavior at small Imageki · kj with the same amplitude in Yang–Mills theory.

6.10 Carry out the integral in eq. (6.6.5) to obtain the Virasoro–Shapiro amplitude (6.6.10). The relation

Image

is useful. (Reference: Green, Schwarz, & Witten (1987), section 7.2; note that their d2z is Image times ours.)

6.11 (a) Verify the amplitude (6.6.14).
(b) Verify the relation (6.6.15) between vertex operator normalizations.
(c) Complete the field theory calculation and verify the relation (6.6.18) between gc and the gravitational coupling.

6.12 Calculate the disk amplitude with one closed string tachyon and two open string tachyons.

6.13 (a) Find the PSL(2, C) transformation that takes three given points z1,2,3 into chosen positions Image1,2,3.
(b) Verify the Möbius invariance results (
6.7.3)–(6.7.7). Show that to derive (6.7.5) it is sufficient that L1 and Image1 annihilate the operators.

6.14 (a) Find the PSL(2, R) transformation that takes three given points y1,2,3 into chosen positions Image1,2,3.
(b) Generalize the Möbius invariance results (
6.7.3)–(6.7.7) to operators on the boundary of a disk.
(c) Find similar results for the disk with one interior, two interior, and one interior and one boundary operators.

6.15 (a) Generalize the operator calculation (6.7.24) to a product of n exponentials.
(b) Generalize it to the expectation value (6.2.25).

__________

1  A curious factor of i has been inserted into eq. (6.2.6) by hand because it is needed in the S-matrix, but it can be understood formally as arising from the same rotation. If we rotated the entire field X0 → − iX d, the Jacobian should be 1, by the usual argument about rescaling fields (footnote 1 of the appendix). However, we do not want to rotate Image, because this mode produces the energy delta function. So we have to rotate it back, giving a factor of i.

2  The constant Image also depends on the conformal factor, because the XImage CFT by itself has nonzero central charge, but in the full string theory this will cancel.

3  Because its Laurent expansion has no factor of i, the Faddeev–Popov c ghost is actually anti-Hermitean under the Euclidean adjoint. This is due to an inconvenient conflict between conventions, and has no significance.